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Colt1911 [192]
3 years ago
11

What could you do in an experiment to get more accurate results?

Chemistry
2 answers:
marissa [1.9K]3 years ago
4 0
I believe it’s b, correct me if i’m wrong
alexandr1967 [171]3 years ago
4 0
It will be D because it is always good practice to take more than five recordings/results/observations so that if you realize that the results vary a bit, you can find the average.
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Scientists discover remains of wooden structures near a Celtic runes site. What kind of testing will indicate when the stones we
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Answer:

Carbon

Explanation:

Bc i got this question on my test

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3 years ago
Consider this reaction mechanism:
tester [92]

Answer:

c)Mo(CO)6 + P(CH3)3  Mo(CO)5P(CH3)3 + CO

-cause i took the test on engenuity

8 0
3 years ago
All cells in living organisms undergo cellular respiration. The chemical reaction for cellular respiration is stated below. (Glu
Ne4ueva [31]

Answer : The total mass of carbon dioxide and water produced will be, 65.7 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of C_6H_{12}O_6+6O_2 = Total mass of 6CO_2+6H_2O

As we are given :

Total mass of C_6H_{12}O_6+6O_2 = 65.7 grams

So,

65.7 grams = Total mass of 6CO_2+6H_2O

Therefore, the total mass of carbon dioxide and water produced will be, 65.7 grams.

4 0
4 years ago
A 52.0 mL portion of a 1.20 M solution is diluted to a total volume of 278 mL. A 139 mL portion of that solution is diluted by a
RoseWind [281]

Answer:

C_3=0.125M

Explanation:

Hello!

In this case, we can divide the problem in two steps:

1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:

V_1C_1=V_2C_2

So we solve for C2:

C_2=\frac{C_1V_1}{V_2}=\frac{52.0mL*1.20M}{278mL}\\\\C_2=0.224M

2. Now, since 111 mL of water is added, we compute the final volume, V3:

V_3=139+111=250mL

So, the final concentration of the 139 mL portion is:

C_3=\frac{139 mL*0.224M}{250mL}\\\\C_3=0.125M

Best regards!

8 0
3 years ago
That gas can be used in mixtures with nitrogen gas to ripen bananas just before they are put on the grocery shelf. This mixture
Sphinxa [80]

Answer:

C2H4

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The image attached shows a detailed solution of the above problem. The empirical formula shows the ratio of the atoms of each element present.

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