All categories

3 years ago

Which of the following affect friction (you can choose more than 1)

Physics

2 answers:

Murljashka [212]3 years ago

6 0

The friction will be mostly affected by roughness of the surface and weight of the object.

Answer: Both B & D

Explanation

Friction is the resisting force acting on an object which is on motion on another object or surface. It is a contact force.

Thus the frictional force depends on the two factors,

(i) the nature of the surface of two objects and

(ii) the mass of the object which needs to moved.

It is known that frictional force is maximum if the surface is roughest.

The smooth surface have less friction so we can move an object easily on a smooth polished surface with less energy than on a rocky surface.

Also from Newton's second law, it is known that any kind of force is directly proportional to the mass of the object and acceleration exerted by the object (F=ma).

As friction is also a kind of force, the influence of mass will be definitely acting on the frictional force.

An object with heavy weight tends to have greater frictional force than on object with less weight.

Anastaziya [24]3 years ago

4 0

I think it would be WEIGHT and ROUGHNESS OF SURFACE.

You might be interested in

Choose the 200 kg refrigerator. Set the applied force to 400 N (to the right). Be sure friction is turned off.What is the net fo

White raven [17]

So, there should be two forces acting on the refrigerator: the applied force and the friction force.

The question mentioned that the friction force was set to zero, so the only effective force now would be the applied force.

We have an applied force of 400 N to the right, this means that:
The magnitude of the net force is 400, directed to the right.

3 0

3 years ago

Read 2 more answers

What is a Cell? Don't look it up PLEASE... I WILL GIVE BRAINLIEST

Travka [436]

Explanation:

Cell is a structural and fundamental unit mass of the body

6 0

2 years ago

A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate

Olegator [25]

Answer:

See the answers below.

Explanation:

In order to solve this problem we must use the principle of energy conservation. Which tells us that the energy of a body will always be the same regardless of where it is located. For this case we have two points, point A and point B. Point A is located at the top at 120 [m] and point B is in the middle of the cliff at 60 [m].

$E_{A}=E_{B}$

The important thing about this problem is to identify the types of energy at each point. Let's take the reference level of potential energy at a height of zero meters. That is, at this point the potential energy is zero.

So at point A we have potential energy and since a velocity of 18 [m/s] is printed, we additionally have kinetic energy.

$E_{A}=E_{pot}+E_{kin}\\E_{A}=m*g*h+\frac{1}{2}*m*v^{2}$

At Point B the rock is still moving downward, therefore we have kinetic energy and since it is 60 [m] with respect to the reference level we have potential energy.

$E_{B}=m*g*h+\frac{1}{2}*m*v^{2}$

Therefore we will have the following equation:

$(6.5*9.81*120)+(0.5*6.5*18^{2} )=(6.5*9.81*60)+(0.5*6.5*v_{B}^{2} )\\3.25*v_{B}^{2} =4878.9\\v_{B}=\sqrt{1501.2}\\v_{B}=38.75[m/s]$

The kinetic energy can be easily calculated by means of the kinetic energy equation.

$KE_{B}=\frac{1}{2} *m*v_{B}^{2}\\KE_{B}=0.5*6.5*(38.75)^{2}\\KE_{B}=4878.9[J]$

In order to calculate the velocity at the bottom of the cliff where the reference level of potential energy (potential energy equal to zero) is located, we must pose the same equation, with the exception that at the new point there is only kinetic energy.

$E_{A}=E_{C}\\6.5*9.81*120+(0.5*9.81*18^{2} )=0.5*6.5*v_{C}^{2} \\v_{c}^{2} =\sqrt{2843.39}\\v_{c}=53.32[m/s]$

5 0

3 years ago

Among the alkali earth metals, the tendency to react with other substances

padilas [110]

Answer D
In alkali earth metals reacrivity increases from top to bottom (opposite of b)
This is because as you go down, the electron shells increase by 1 shell. The farther away a shell is from the nucleus, the higher its tendency to react.
D is true because the more reactive an alkali metal is, the more vigorous the reaction will be with water.

4 0

2 years ago

Read 2 more answers

At what water temperature will additional heat energy need to be added before the temperature will change again?

Lostsunrise [7]

That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)

6 0

3 years ago