As a student How can you be literate in media and information but about my mother's knowledge

Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as eit

suter [353]

Explanation:

Molecular equation: Chemical equation in which molecular formula of reactants and products are written

Complete ionic equation:Chemical equation in which ionic from if reactants reactants and products are written along with spectator ions (ions present on both sides of equation).

Net ionic equation :Chemical equation in which only ions of those reactant are written which giving product without spectator ions (ions present on both sides of equation).

(a) $Ca^{2+}(aq) + SO_4^{2-}(aq)\rightarrow CaSO_4(s)$

net ionic equation.

(b) $CuSO_4(aq) + 2KOH(aq)\rightarrow Cu(OH))_2(s) + K_2SO_4(aq)$

Molecular equation

(c) $Ba^{2+} (aq) + SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

Net ionic equation.

(d) $Ag^+(aq) + NO_{3}^-(aq) + I^-(aq)\rightarrow AgI(s) + NO_{3}^-(aq)$

Complete ionic equation

3 0

4 years ago

A glass sphere is filled to full volume with a gas. The pressure of the gas inside the sphere is 30.0 atm, and the temperature i

harkovskaia [24]

Answer:

28atm

Explanation:

Using Gay lussac's law equation as follows:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

T1 = initial temperature (K)

P2 = final pressure (atm)

T2 = final temperature (K)

Based on the information provided in this question;

P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C

NOTE: Absolute temperature i.e. Kelvin is required for this law

T1 = 30°C + 273K = 303K

T2 = 10°C + 273K = 283K

Using P1/T1 = P2/T2

30/303 = P2/283

Cross multiply

P2 × 303 = 30 × 283

303P2 = 8490

P2 = 8490/303

P2 = 28.02

New pressure of the gas = 28atm

4 0

3 years ago

Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h

IgorC [24]

Mass in kilograms of liquid air required = 0.78 kg

Given that

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

Determine the amount of liquid air in Kg

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L = x

∴ x ( mass of liquid air ) = 1.3 * 600

= 780 g = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

3 0

2 years ago

Read 2 more answers

Which weighs more 10g of iron or 10g of water

Svet_ta [14]

Neither. They are both 10 grams so they weigh the same.

4 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Soloha48 [4]

Before it is released it as potential energy and after it has been released it transforms into kinetic energy.

7 0

3 years ago

As a student How can you be literate in media and information but about my mother's knowledge​

As a student How can you be literate in media and information but about my mother's knowledge