We determine the percent by mass of water in the compound by dividing the mass of water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g.
percent by mass of water = (180 / 322)*(100 %) = 55.9%
"(2) increase in suburbanization" was a direct result of the <span>baby boom that followed World War II, but of course there were other factors that resulted as well. </span>
B will be the one I think tbh
Answer:
5000 and 
indicate that there is more B than A at equilibrium
Explanation:
For the given reaction: ![K=\frac{[B]}{[A]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D)
where [B] and [A] represents equilibrium concentration B and A respectively. K represents equilibrium constant
More B than A at equilibrium means, [B] > [A]
So, ![K=\frac{[B]}{[A]}>1](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BB%5D%7D%7B%5BA%5D%7D%3E1)
As, both 5000 and are greater than 1 therefore these two K values indicate that there is more B than A at equilibrium
