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Aleonysh [2.5K]
3 years ago
11

Recall the relationship between the charge on a capacitor and the potential difference across the capacitor. Use this relationsh

ip to describe how you could use a voltmeter to determine the charge on a capacitor.
Physics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

Answer in explanation.

Explanation:

The relationship between the charge on the capacitor and the potential difference across it is given as follows:

Q = CV

where,

Q = Charge on the Capacitor

C = Capacitance of the Capacitor

V = Potential Difference across the Capacitor

This relationship can be used to find the charge on a capacitor, using the voltmeter, as follows:

<u>The potential difference can be measured through the voltmeter. And the capacitance of the capacitor is a known constant value. Therefore, the charge can be found by taking product of both.</u>

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Svetlanka [38]

Answer:

ΔV=0.484mV

Explanation:

The potential difference across the end of conductor that obeys Ohms law:

ΔV=IR

Where I is current

R is resistance

The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A

R=(pL)/A

Given data

Length L=3.87 cm =0.0387m

Diameter d=2.11 cm =0.0211 m

Current I=165 A

Resistivity of aluminum p=2.65×10⁻⁸ ohms

So

ΔV=IR

=I(\frac{pL}{A})\\ =I(\frac{pL}{\pi r^{2} } )\\=I(\frac{pL}{\pi (d/2)^{2} } )\\=165A((\frac{(2.65*10^{-8})(0.0387m)}{\pi (0.0211m/2)^{2} } ))\\=4.84*10^{-4}V

ΔV=0.484mV  

3 0
3 years ago
You just landed a job as an assistant to an electrician who is working on a building site. He is making use of long single-condu
Anit [1.1K]

Answer:

R/l = 0.25925 Ω / m

Explanation:

Ohm's law says that the potential difference is proportional to the product of the resistance by the current

         V = I R

         R = V / I

In this case, since we have two lengths, we can have two lengths, we can find the resistance for each

         L = 5 m

         R = 7.70 / 5.47

         R = 1,408 Ω

         L = 10 m

         R = 7.70 / 3.25

         R = 2,369 Ω

We can make a direct proportions rule (rule of three) to find the resistance per unit length

For L = 5 m

         R/l = 1,408 / 5

         R/l = 0.2816 Ω / m

For L = 10 m

        R/l = 2,369/10

        R/l = 0.2369 Ω / m

We can see that the value is similar that differs from the second decimal place, in this case the value for the longer re wire is more accurate because it has a lower joule effect.

One way also to find the average value

       R/l = (0.2816 + 0.2369) / 2

       R/l = 0.25925 Ω / m

3 0
3 years ago
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Suppose you were examining a pulsing radio signal from a stellar remnant in a distant part of the Milky Way. Knowing that ionizi
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Answer:

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Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an
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Answer:

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SOLID SPHERE:

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HOLLOW SPHERE

I_{hs} = \frac{2}{3}mR^2

If we have the same acceleration for a Torque applied, then

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The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

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3 years ago
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