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Juli2301 [7.4K]
3 years ago
15

The ability to move or change an object or what a wave carries

Physics
1 answer:
Sever21 [200]3 years ago
5 0

Answer: The ability to move or change an object or what a wave carries is called Energy

Explanation: Waves are disturbances in physical quantities. Example of waves are light waves, sound waves, or transverse oscillations of a string. These disturbances use energy to create and propagate, for it to move the constituent particles or change the electric or magnetic fields. Therefore, power of a wave is therefore, energy transported divided by unit time caused by the oscillations of a particular wave. The derivation of a formula for the power depends on the medium -- for light waves, the power is measured by the pointing vector, whereas for oscillations on a string, the power can be computed directly by balancing forces through the application of newton law. However, for all types of waves, the formula and physical meaning of the power takes similar forms, typically depending on the square amplitude of the waves among other factors.

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5. An electrical power plant generates electricity with a current of 50 A and a potential difference of 20 000 V. In order to mi
lakkis [162]

Answer: Current = 2 A

Explanation:

Given that an electrical power plant generates electricity with a

current I = 50 A

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The resistance R will be achieved by Ohms law formula which state that

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But the power generated will be the product of potential difference and the current

Power P = IV

P = 50 × 20000

P = 1, 000000 W

When the transformer steps up the potential difference to 500 000 V before it is transmitted

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Using the formula for power again with

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3 years ago
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almond37 [142]

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Explanation:

You should start off from the decay formula and solve for τ:

I = I_{0}e^{\frac{t}{\tau\\  } }

\frac{I}{I_{0}} = e^{\frac{-t}{\tau} }

Apply inverse logarithmic function:

ln(\frac{0.2 A}{1.2 A} ) = \frac{-t}{\tau}

The final form will be:

\tau=\frac{-3.5s}{ln(\frac{0.2A}{1.2A} )}

Inputing values for I, IO, and t:

\tau=\frac{-3.5S}{ln(\frac{0.2 A}{1.2 A} )} = 1.95

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Answer:

soluble

Explanation:

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