12gHe/1 × 1molHe/4.0026g × 6.02x10^23atomHe/1mol = 1.8 atoms
Answer:
- <u><em>1.12 liters</em></u>
Explanation:
<u>Calculating number of moles</u>
- Molar mass of O₂ = 32 g
- n = Given weight / Molar mass
- n = 1.6/32
- n = 0.05 moles
<u>At STP</u>
- One mole of O₂ occupies 22.4 L
- Therefore, 0.05 moles will occupy :
- 22.4 L x 0.05 = <u><em>1.12 L</em></u>
Answer:
Explanation:
[ so₃] = 4.37 x 10⁻²
[so₂] = 4.77 x 10⁻²
[ o₂] = 4.55 x 10⁻²
Qc = (4.37)²x10⁻⁴ /(4.77)².(4.55) x 10⁻⁶ =18.44
Qc is less than Kc hence in order to reach equilibrium more of so₃ will be produced . Statement 1 is true.
Kc is always constant . Statement 2 is false.
Statement 3 is false because statement 1 is true.
Qc Is smaller than Kc . So statement 4 is false.
The reaction is not in equilibrium. Statement 5 is false.
The answer is d. hope it helps
