Three capacitors (4.7, 6.5, and 15.5 F) are connected in series across a 50.0-V battery. Find the voltage across the 4.7-F capac
1 answer:
Answer: 50 V
Explanation:
Given
Three capacitors are connected in parallel across 50 V battery
When capacitor are connected in parallel, net capacitance is the sum of all the values
Net capacitance
Voltage in parallel circuit is same across each capacitor. Therefore, voltage across 4.7 F capacitor is 50 V
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Answer: 117 kPa
Explanation:
For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa
For the liquid at depth 9m, the gauge pressure is equal to= P₂
Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.
So, For finding gauge pressure we have formula P= ρ * g * h
Also gravity also remains same for both liquids
So taking ratio of their respective pressures we have
=
So =
Or P₂= 39 * 3 = 117 kPa