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drek231 [11]
3 years ago
10

Three capacitors (4.7, 6.5, and 15.5 F) are connected in series across a 50.0-V battery. Find the voltage across the 4.7-F capac

itor
Physics
1 answer:
satela [25.4K]3 years ago
6 0

Answer: 50 V

Explanation:

Given

Three capacitors are connected in parallel across 50 V battery

When capacitor are connected in parallel, net capacitance is the sum of all the values

Net capacitance

\Rightarrow C=4.7+6.5+15.5\\\Rightarrow C=26.7\ F

Voltage in parallel circuit is same across each capacitor. Therefore, voltage across 4.7 F capacitor is 50 V

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Answer: 0m/s²

Explanation:

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Ff = nR where

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Substituting in the formula of newton's first law we have;

Fm-Ff = ma

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Given

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Substituting in eqn 1,

562sin30° - tan30°(562cos30°) = 56.2a

281 - 281 = 56.2a

0 = 56.2a

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