Answer:
5 minutes ago A bird flies 6km east, then 4km west. Find the total distance traveled and displacement (d) after this flight. Find the total distance traveled and displacement (d) after this flight.
Explanation:
The transfer of internal energy in the form of electromagnetic waves.
Answer:
a)5m b)5secs c) 10secs
Explanation:
a) maximum height H = u²/2g
Given u = 50m/s
g = 10m/s²
H = 10²/20
H= 5m
maximum height reached by the rocket is therefore 5m
.b)Time it takes the rocket to reach its maximum height is Tmax = U/g
Tmax = 50/10
Tmax = 5seconds
c) How long the rocket spent in the air is the time of flight T
T = 2U/g
T = 2×50/10
T = 100/10
T = 10seconds
Answer:
5.76 μC
Explanation:
The induce emf, ε = -ΔΦ/Δt where ΔΦ = change in magnetic flux = NAΔB where N = number of turns of coil = 1000, A = cross-sectional area of coil = πd²/4 where d = diameter of coil = 2 cm = 2 × 10⁻² m and ΔB = change in magnetic field strength = B' - B where B' = final magnetic field = 0 T and B = initial magnetic field strength = 0.011 T. So, ΔB = 0 T - 0.011 T = -0.011 T
So, ε = -ΔΦ/Δt
ε = -NAΔB/Δt
ε = -NAΔB/Δt
Also ε = iR where i = current and R = combined resistance of circular coil and galvanometer = 200 Ω + 400 Ω = 600 Ω (since they are in series)
So, iR = -NAΔB/Δt
iΔt = -NAΔB/R
Δq = -NAΔB/R where Δq = charge = iΔt
substituting the values of the variables into the equation, we have
Δq = -1000 × π(2 × 10⁻² m)²/4 × -0.011 T/600 Ω
Δq = -1000 × 4π × 10⁻⁴ m²/4 × -0.011 T/600 Ω
Δq = 0.011π × 10⁻¹ m²T/600 Ω
Δq = 0.03456 × 10⁻¹ m²T/600 Ω
Δq = 5.76 × 10⁻⁶ C
Δq = 5.76 μC
Answer:
140 m/s
Explanation:
v = u + at
v = 8 + 3.5(40) = 140 + 8 = 140