viruses are made of proteins and contain genetic information to produce more of them in the form of DNA or RNA.
The answer is A) Water has surface tension.
This is the correct answer because water allows animals and really light items to rest upon the top of the water.
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Answer:
155.4 g of Al₂O₃
Explanation:
The reaction is:
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
To determine the mass of aluminum oxide that is formed we need to know the limiting reagent. Let's calculate the moles of each by the molar mass
Mass / molar mass = Moles
82.49 g / 26.98 g/mol = 3.05 moles of Al
117.65 g / 32 g/mol = 3.67 moles of oxygen
Let's try the oxygen. Ratio is 3:4.
3 moles of O₂ need 4 moles of Al to react
Therefore 3.67 moles of O₂ will react with (3.67 . 4 )/3 = 4.90 moles
We only have 3.05 moles of Al, so the Al is the limiting reactant
Now, we work with stoichiometry
4 moles of Al can produce 2 moles of Al₂O₃
3.05 moles of Al will produce (3.05 .2) / 4 = 1.52 moles of Al₂O₃
We convert the moles to mass: 1.52 mol . 101.96 g / 1mol = 155.4 g
Answer:
Density of copper = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Explanation:
Given data:
weight of copper metal = 1896 g
Dimensions of block = 8.4 cm, 5.5 cm, 4.6 cm
Density of copper = ?
Will it float to the liquid mercury = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
volume of coper metal = 8.4 cm × 5.5 cm × 4.6 cm
volume of coper metal =212.52 cm³
d = 1896 g/ 212.52 cm³
d = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Answer:
Light and sound both are waves, but sound requires a material medium to travel, and hence cannot travel in empty space while light can travel through vacuum but not through opaque materials. Both undergo refraction, diffraction and interference.
Explanation: