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uysha [10]
3 years ago
9

A 200. Kg load of bricks is to be lifted from the ground to the top of a 30.0 m high building in 30.0 s. If a 75.0 N frictional

force in the pulley opposes motion, what minimum power motor would be needed?
Physics
1 answer:
coldgirl [10]3 years ago
3 0

Answer:

The minimum power the motor would need is 2035 Watts.

Explanation:

the minimum power motor needed is given by the total work done on the load, Wtot and the total time it takes the load to be lifted, given by:

P = Wtot/t

the forces doing works on the load is the gravitational force, Wfg and the frictional force, Wf the total work done on the load is:

Wtot = Wfg + Wf

        =  m×g×d + f×d

        = d×(m×g + f)

        = (30)×(200×9.8 + 75)

         = 61050 J

it takes t = 30s for the load to be lifted high the building, the minimum power neeed is then:

P = Wtot/t

  = (61050)/(30)

  = 2035 Watts

Therefore, the minimum power the motor would need is 2035 Watts.

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Which statement correctly describes the relationship between the volume of a gas and its temperature, in Kelvin, assuming pressu
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5 0
3 years ago
A 300 kg car initially travels with a velocity of 20 m/s to the right. A net force F acts on the car for 5 s, which causes the v
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Answer:

<em>600N.</em>

Explanation:

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Recall that: F = m(v-u)/t

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<em>Hence the net force acting on the car is 600N.</em>

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