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3 years ago

5. Extend your thinking: What strategies did you use to hunt for moths?

1 answer:

8 0

Answer: There are many strategies used to hunt and kill moths. I’ll tell you my way of hunting and killing moths.

Step-By-Step Explanation:
Morning and Afternoon: First, get a sticky trap. You can get it at Target or Walmart. Cover it with moth pheromones or anything you know that can attract the moths. The sticky trap, will stick them to the trap and will eventually die after no being able to escape for a long time.
Nighttime: Buy or Get a lamp and turn it on. This will attract lots of moths and it will help you see them. Then, spray insecticide or insect repellent at the. Lastly, they should die.
Tip: If things get too out of hand with a huge swarm of moths, then call pest control and they will surely get rid of them for you!

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When does the electron shown release the greatest amount of energy as it moves from one level to another?

ELEN [110]

S1 to GS as the amount of energy required to remove the electron is greatest when it is closest to the nucleus. think about two magents. does it take more energy to spereate them when they are far apart or when they are very close together? it's the same idea with electrons. the more energy required to remove, the more energy will be emmitted.

8 0

3 years ago

If the pOH of a nitric acid (HNO3) solution is measured as 11, what is the concentration of HNO3 solution?

Illusion [34]

1 gram of HNO3 will be equal to 1/63.01 moles. Therefore, we can say that 1 liter of Nitric acid contains 15.6976 moles or in other words molarity of 70% (w/w) Nitric acid is equal to 15.6976 M.

Known values

Molecular weight of HNO3 63.01 g/mole

Concentration of Nitric acid 70% (% by mass, wt/wt)

4 0

2 years ago

Suppose the half-life of element k is 20 minutes. if you have a 200 g sample of k, how much of element k will be left after 60 m

vodka [1.7K]

T=20 min
m₀=200 g
t=60 min

the mass of element through time t is:
m=m₀*2^(-t/T)

m=200*2^(-60/20)=25 g

25 grams of element will be left after 60 minutes

5 0

3 years ago

Read 2 more answers

-FeS2+-O2->-Fe2O3+-SO2 What coefficient should be placed in front of SO2 to balance the equation?

NISA [10]

Answer:

8 should be placed in front of SO₂.

Explanation:

The easiest way to solve this question is by writing the entire balanced equation:

4FeS₂ + 11O₂ -> 2Fe₂O₃ + 8SO₂

We can achieve this by first balancing the Fe, then S, and finally the O.

We can also double check our answer by counting the number of each element on both sides:

-Reactants: 4 Fe, 8 S, 22 O

-Products: 4 Fe 8 S, 22 O

Since they match, our equation is balanced, and the coefficient in front of SO₂ is 8.

8 0

3 years ago

On the space shuttle, lithium hydroxide is produced from lithium oxide and water. The lithium hydroxide then reacts with the exh

Ratling [72]

Answer:

6,2g of CO₂

Explanation:

Based on the reactions:

Li₂O(s) + H₂O(g) → 2LiOH(s)

LiOH(s) + CO₂(g) → LiHCO₃(s)

2,6g of Li₂O and 1,3g of H₂O are:

2,6g × ( 1mol / 29,88g) = 0,087 moles

1.3g × ( 1mol / 18,01g) = 0,072 moles

That means limiting reactant is H₂O. The moles produced of LiOH are:

0,072 moles of H₂O × ( 2mol LiOH / 1mol H₂O) = 0,14 moles of LiOH

Thus, the maximum CO₂ that can react are 0,14 moles of CO₂, in grams

0,14 moles CO₂ × (44,01g / 1mol) = 6,2g of CO₂

I hope it helps!

6 0

3 years ago