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ollegr [7]
3 years ago
11

Presuming you have a closed circuit, when you thrust a bar magnet to and fro into a coil of wire, you induce:________.

Physics
1 answer:
Art [367]3 years ago
7 0
Hedndjf Hinduism’s jeirbduddn dudurnidkd idbehdududid idjdjdudud idjdbdudud idisjdbdbd
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What is an electromagnetic wave?
satela [25.4K]
I think it is B. Sorry if I’m wrong
6 0
2 years ago
The product PV, where P and V represent pressure and volume respectively, is a unit for which?
Basile [38]
<span>PV is actually energy. P = F/A force per area, and V = A L, so PV = F L and force times distance is work which is energy. If you have P in N/m^2 and V in m^3, you have Joules, N-m.</span>
6 0
3 years ago
The human ear canal is about 2.3 cm long. If it is regarded as a tube open at one end and closed at the eardrum, what is the fun
mariarad [96]

Answer:

For the given conditions the fundamental frequency is 3728.26 Hertz

Explanation:

We know that for a pipe open at one end and closed at other end the fundamental frequency is given by

f=\frac{V_{s}}{4L}

where

f is the fundamental frequency

V_{s} is the speed of sound in air in the surrounding conditions.

L = Length of the pipe

Applying values we get and using speed of sound as 343m/s we get

f=\frac{343}{4\times 2.3\times 10^{-2}}=3728.26Hz

7 0
2 years ago
A net force of 10.0 N causes an object to accelerate at 2.00m/s^2. What is the mass of the object?
madam [21]

5.00kg

random = abcdefghijklmnopqrstuvwxyz


4 0
3 years ago
Consider a stone in free fall on a planet with gravitational acceleration 3.4 m/s^2. Suppose you would like the stone to experie
Stella [2.4K]

Answer:

Angle of incline is 20.2978°

Explanation:

Given that;

Gravitational acceleration on a planet a = 3.4 m/s²

Gravitational acceleration on Earth g = 9.8 m/s²

Angle of incline = ∅

Mass of the stone = m

Force on the stone along the incline will be;

F = mgSin∅

F = ma

The stone has the same acceleration as that of the gravitational acceleration on the planet.

so

ma = mgSin∅

a = gSin∅

Sin∅ = a / g

we substitute

Sin∅ = (3.4 m/s²) / (9.8 m/s²)

Sin∅ = 0.3469

∅ = Sin⁻¹( 0.3469 )

∅ = 20.2978°

Therefore, Angle of incline is 20.2978°

8 0
3 years ago
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