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zlopas [31]
3 years ago
13

Which of the following combinations would form a buffer solution?

Chemistry
1 answer:
Schach [20]3 years ago
6 0

Answer:

d . all of the above

Explanation:

A buffer system can be formed in one of two ways:

  • A weak acid and its conjugate base
  • A weak base and its conjugate acid

Which of the following combinations would form a buffer solution?

a. HF and LiF. YES. HF is a weak acid and F⁻ (from LiF) is its conjugate base.

b. NH₃ and NH₄Br. YES. NH₃ is a weak base and NH₄⁺ (from NH₄Br) is its conjugate acid.

c. HNO₂ and NaNO₂. YES. HNO₂ is a weak acid and NO₂⁻ (from NaNO₂) is its conjugate base.

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For answering for the question, there exists four choices:
1) Na+  +  e- -------------- Na
2) Na --------Na+   +  e-
3) Cl2 +   2e-  ------------ Cl-
4) 2Cl-  ---------Cl2 +  2e-

reduction half-reaction general formula is 
oxidant + e - or +  -------- Product

so in our case the answer is 
1) Na+  +  e- -------------- Na (exactly balanced)

6 0
4 years ago
Mass = 35g Volume = 7cm3 What is the Density?​
olga_2 [115]

Answer:

5 g/cm^3

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7 0
3 years ago
A motorcycle travel at 6.0 m/s. After 3.0 second, the motorcycle travel at 15.0 m/s. Which of the following was the average acce
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Hello!

\large\boxed{a = 3m/s^{2}}

Use the following equation to solve for the average acceleration of the motorcycle:

a = \frac{v_{f}-v_{i}}{t}

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a = \frac{15-6}{3}\\\\a = \frac{9}{3}\\\\a = 3m/s^{2}

7 0
3 years ago
If a liquid has a Ph of 3 what is it​
kvasek [131]
Lower than 7 is acid greater than 7 is a base
6 0
4 years ago
On the axes provided, label pressure on the horizontal axis from O mb to 760 mb and volume on the vertical axis from O to 1 mL.
Delicious77 [7]

Answer:

  • Please, find the graph with the labels and points located on the axes in the picture attached.

Explanation:

This is how you meet all the instructions and some important comments to understand how this kind of graphs word:

<u>1) Label pressure on the horizontal axis from O mb to 760 mb and volume on the vertical axis from O to 1 mL. </u>

The horizontal axis is used to record the independent variable and the vertical axis is used to record the dependent variable. The axes most be properly labeled with the name of the variable and the units.

In this case the origin is the point (0,0) which means that the axes cross each other, perpendicularly, at a pressure of 0 mb and a volume of 0.0 mililiters.

<u>2) Assign values to axes divisions in such a way that you occupy almost all the space on both axes. </u>

A good graph searches to occupy the whole space on both cases; to do that, find the maximum value for each variable, pressure and volume, and choose the values of the marks.

The range of the pressure (horizontal axis) is [90, 760 mb], so you should choose big divisions (marks) of 100 mb, and assign 800 mb to the right most mark on the horizontal axis. Then, you can divide each interval of 100 mb into 10 spaces, with small divisions of 10 mb (my graph uses 4 spcaes, with small divisions of 25 mb, but I recommend you use small divisions of 10 mb).

The range of the volume (vertical axis) is [0.1, 0.8], so you should choose only divisions with value of 0.1 ml.

<u>3) Now locate and label the points: </u>

  • (90, 0.9) ⇒ 90 mb, 0.9 ml
  • (100, 0.8) ⇒ 100 mb, 0.8 ml
  • (400, 0.2) ⇒ 400 mb, 0.2 ml
  • (600, 0.15) ⇒ 600 mb, 0.15 ml
  • (760, 0.1) ⇒ 760 mb, 0.1 ml

The points of the kind (x, y) are called ordered pairs, which means that the order matters, because it has a meaning: the first number represents the independent variable and the second number represents the dependent variable.

So, in the point (90, 0.9), 90 is a pressure of 90 mb and 0.9 is a volume of 0.9 ml.

To locate (600, 0.15), since the horizontal marks have value of 0.1, you must locate the second coordinate of your point between the marks 0.1 and 0.2 ml.

With that you can now locate each point on your graph.

5 0
3 years ago
Read 2 more answers
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