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2 years ago

Which of the following combinations would form a buffer solution?

Chemistry

1 answer:

Schach [20]2 years ago

6 0

Answer:

d . all of the above

Explanation:

A buffer system can be formed in one of two ways:

A weak acid and its conjugate base
A weak base and its conjugate acid

Which of the following combinations would form a buffer solution?

a. HF and LiF. YES. HF is a weak acid and F⁻ (from LiF) is its conjugate base.

b. NH₃ and NH₄Br. YES. NH₃ is a weak base and NH₄⁺ (from NH₄Br) is its conjugate acid.

c. HNO₂ and NaNO₂. YES. HNO₂ is a weak acid and NO₂⁻ (from NaNO₂) is its conjugate base.

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What is the molarity of a solution containing 8.0 moles of solute in 120mL of solution?

Nataliya [291]

Answer:
200/3 M which is approximately equal to 66.6667 M

Explanation:
Molarity is defined as the number of moles of solute per liter of solution.

It can be calculated as follows:
$molarity = \frac{number of moles of solute}{liters of solution}$

We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters

Substitute with the givens in the above equation to get the molarity as follows:
molarity = $\frac{8}{0.12} = \frac{200}{3} = 66.6667 M$

Hope this helps :)

3 0

2 years ago

what would you be most likely to measure by immsering and object in water and seeing how much the water level rises

Katena32 [7]

Mass, if you know what element you are working with.

4 0

2 years ago

I NEED HELP ASAP!! I DOMT KNOW HOW TO DO THIS

KatRina [158]

What part of it are you confused about

3 0

3 years ago

In order to dry wet clothes, we spread them on a clothline. This is because (i) spreading increases surface area (ii) clothes be

Novosadov [1.4K]

Answer:

this is because spreading it makes more sunlight hit the cloth which results in it drying faster

3 0

3 years ago

The half life of 226/88 Ra is 1620 years. How much of a 12 g sample of 226/88 Ra will be left after 8 half lives?

Aloiza [94]

Answer:

0.0468 g.

Explanation:

The decay of radioactive elements obeys first-order kinetics.

For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).

Where, k is the rate constant of the reaction.

t1/2 is the half-life time of the reaction (t1/2 = 1620 years).

∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.

For first-order reaction: kt = lna/(a-x).

where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).

a is the initial concentration (a = 12.0 g).

(a-x) is the remaining concentration.

∴ kt = lna/(a-x)

(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).

5.54688 = ln(12)/(a-x).

Taking e for the both sides:

256.34 = (12)/(a-x).

∴ (a-x) = 12/256.34 = 0.0468 g.

8 0

2 years ago