Question

Writing Sample: At what pressure would 0.150 mole of nitrogen gas at -23.0 o C occupy 8.90 L?

Answer 1

Answer:

$P=0.346atm$  

Explanation:

Hello!

In this case, since the ideal gas equation is:

$PV=nRT$

And we are asked to compute the pressure, we obtain:

$P=\frac{nRT}{V}$

Thus, since the temperature must be expressed in Kelvins, we plug in to obtain:

$P=\frac{0.150mol*0.08206\frac{atm*L}{mol*K}*250.15K}{8.90L}\\\\P=0.346atm$

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