6.02214086 x 10^23 mol^-1
Answer:1.
Explanation: This reaction is catalyzes by pyruvate dehydrogenase. Pyruvate being the end product of glycolysis has many fates after glycolysis,one of which is to enter the TCA(Tricarboxylic acid cycle) cycle. It is first converted to actetate by the action of pyruvate dehydrogenase. This enzyme converts pyruvate to acetate releasing CO2 and NADH because this oxidative decarboxylation of pyruvate is coupled with reduction of NAD+ which can feed into the electron transport chain.
Given the temperature 746 K and activity of Pb equal to 0.055. The mole fraction of Pb is 0.1. So, the mole fraction of Sn = 0.9.Activity coefficient, γ = 0.055 / 0.1 = 0.55.The expression for w=ln〖γ_Pb x RT〗/(X_Sn^2 )=(-0.5978 x 8.314 J/(mol K ) x 746 K)/(0.9 x 0.9)= -4577.7 J= -4578 J
Now we use the computed value above and new temperature 773 K. The mole fraction of Sn and Pb are 0.5 and 0.5 respectively. Calculate the activity coefficient in the following manner.lnγ_Sn=w/RT X_Pb^2=(-4578 J)/(8.314 J/mol x 773 K) x 0.5 x 0.5= -0.718lnγ_Sn=exp(-0.178)=0.386The activity of Sn= γ_Sn x X_Sn=0.386 x 0.5=0.418
w of the system is -4578 J and the activity of Sn in the liquid solution of xsn at 500 degree Celsius is 0.418
Answer:
here you go. I took the test :)
Explanation:
Answer:
a) 113g Sr3(PO4)2
b) 1.5g H2
Explanation:
The number of moles of Sr used in the equation
= mass/ molar mass
=65.30/87
= 0.751mol
Since the mole ratio of Sr: Sr3(PO4)2 is 3:1
moles of Sr3(PO4)3 = 1/3*0.751
= 0.25mol
grams of Sr3(PO4)3 is = moles * molar mass
= 0.25 * 452
= 113g
b). Since mole ratio of Sr:H2 is 3:3
moles of H2 = 0.751 * 3/3 ---> 0.751 mol
grams of H2 is = moles * molar mass
= 0.751 * 2
= 1.502g
