Since both α and β are in the first quadrant, we know each of cos(α), sin(α), cos(β), and sin(β) are positive. So when we invoke the Pythagorean identity,
sin²(x) + cos²(x) = 1
we always take the positive square root when solving for either sin(x) or cos(x).
Given that cos(α) = √11/7 and sin(β) = √11/4, we find
sin(α) = √(1 - cos²(α)) = √38/7
cos(β) = √(1 - sin²(β)) = √5/4
Now, recall the sum identity for cosine,
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
It follows that
cos(α + β) = √11/7 × √5/4 - √38/7 × √11/4 = (√55 - √418)/28
We have to solve this quadratic equation 
for n to get <em>which figure has 56 blocks</em>.
For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>
<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>
<em>
</em>
<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>
Our answer is 7.
ANSWER: The 7th figure has 56 blocks.
Ok, since y varies inversely as x , the equation is y=k/x....... Then you plug in 2 for y and 25 for x to find K....... After that you get K= 50...... Then plug in 50 for K and 40 for y then solve for x....... After that you get X= 1.25!!!!! :)
Answer:
Hey there!
The equation is x+2x+5+6x-17+3x+2, or 12x-10
12x-10=50
12x=60
x=5
Let me know if this helps :)
Answer:
Number of chaperones = 9
Step-by-step explanation:
Given:
Total number of teacher = 2
Total people attend = 54
Find:
Number of chaperones
Computation:
Assume;
Number of chaperones = x
So,
x = [54-x] / 5
5x = 54 - x
6x = 54
x = 9
Number of chaperones = 9
