The number of liters of 3.00 M lead (II) iodide : 0.277 L
<h3>Further explanation</h3>
Reaction(balanced)
Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
moles of KI = 1.66
From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):
I think it will be letter A tbh
Hope this helps you out
Answer:
Nitropruside
Explanation:
Shock is a serious medical condition where oxygen levels in the body are low, causing a low blood pressure which can lead to organ damage and sometimes death. Shock can be caused by low blood volume or inadequate pumping action of the heart.
Nitropruside is a very potent vasodilator. It acts on the arterial and venous smooth muscles, causing smooth muscle relaxation and leading to decreased cardiac preload and afterload. A reduction in afterload gives rise to an increased cardiac output and blood supply to the cells is increased. This in turn reduces the need for the heart to pump more blood (a compensatory response by the heart due to the low oxygen levels), thereby reducing the oxygen demand of the heart.
Answer:
Add copper (II) oxide (insoluble base), a little at a time to the warm dilute sulfuric acid and stir until the copper (II) oxide is in excess (stops disappearing) Filter the mixture into an evaporating basin to remove the excess copper (II) oxide. Leave the filtrate in a warm place to dry and crystallize.
New molecules would form.
the other three are examples of a physical change
