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2 years ago

13

Is a planar carbon "backbone" possible for propane? Explain.

1 answer:

tankabanditka [31]2 years ago

4 0

Answer:

Cyclopropane has a planar carbon back bone while propane does not

Explanation:

We have to recognize that in straight chain saturated organic compounds, carbon atoms have a tetrahedral geometry. Each carbon atom is bonded to four other atoms.

However, carbon atoms in cyclic compounds are also sp3 hybridized with each carbon bonded to only four other atoms but the ring system is highly strained.

Cyclopropane is a necessarily planar molecule with a bond angle that is far less than the expected tetrahedral bond angle due to strain in the molecule. Hence, the carbon atoms may have have a "planar backbone".

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Definition<br> a visual representation of data that uses unconnected plotted points

Vesna [10]

A horizontal exempted is a bit tight but I think it’s a good idea

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1 year ago

A sample of krypton gas collected at a pressure of 1.31 atm and a temperature of 26.0°C is found to occupy a volume of 23.3 lite

djyliett [7]

Mol of Kr gas = 1.244

<h3>Further explanation</h3>

In general, the gas equation can be written

<h3> PV=nRT </h3>

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08205 L.atm / mol K

T = temperature, Kelvin

P=1.31 atm

V=23.3 L

T=26+273=299 K

mol of sample :

$\tt n=\dfrac{PV}{RT}=\dfrac{1.31\times 23.3}{0.08205\times 299}=1.244$

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3 years ago

What is abbreviated structural formula of the 2-metil-5-isopropiloctan?

Alja [10]

Answer:

CH3

|

CH3- C H -CH2-CH2- CH - CH2-CH2-CH3

|

CH

/ \

CH3 CH3

Explanation:

Octan

C-C-C-C-C-C-C-C

Metyl

CH3 -

Isopropyl

CH3

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CH3

2-metil-5-isopropiloctan

CH3

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3 years ago

Sometimes a cloud may form at or near the ground when the ground cools at night. This cloud is known as...

melomori [17]

Answer:

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2 years ago

Read 2 more answers

How much heat is released when you condense 93.9 g of water vapor? <br><br> Show work please ❤️

sammy [17]

<u>Answer:</u>

211.9 J

<u>Explanation:</u>

The molecules of water release heat during the transition of water vapor to liquid water, but the temperature of the water does not change with it.

The amount of heat released can be represented by the formula:

$Q=mL_e$

where $Q$ = heat energy, $m$ = mass of water and $L$ = latent heat of evaporation.

The latent heat of evaporation for water is $L=2257 kJ/kg$ and the mass of the water is $m=93.9 g=0.0939 kg$ .

The amount of heat released in this process is:

$Q=mL_e = (0.0939kg)(2257 kJ/kg)=$ 211.9 J

7 0

3 years ago