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3 years ago

What subatomic particles do the following symbols represent in the atomic diagrams

Chemistry

1 answer:

timofeeve [1]3 years ago

3 0

Answer:

protons

neutrons

helium

Explanation:

it is correct

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The elementary reaction 2H2O(g)↽−−⇀2H2(g)+O2(g) 2H2O(g)↽−−⇀2H2(g)+O2(g) proceeds at a certain temperature until the partial pres

Dima020 [189]

Answer:

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

Explanation:

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of products to the partial pressures of reactants each raised to the power equal to their stoichiometric ratios. It is expressed as $K_{p}$

$2H_2O(g)\rightleftharpoons 2H_2(g)+O_2(g)$

Partial pressures at equilibrium:

$p^o_{H_2O}=0.070 atm$

$p^o_{H_2}=0.0035 atm$

$p^o_{O_2}=0.0025 atm$

The equilibrium constant in terms of pressures is given as:

$K_p=\frac{(p^o_{H_2})^2\times (p^o_{O_2})}{(p^o_{H_2O})62}$

$K_p=\frac{(0.0035 atm)^2\times 0.0025 atm}{(0.070 atm)^2}=6.25\times 10^{-6}$

$6.25\times 10^{-6}$ is the value of the equilibrium constant at this temperature.

5 0

3 years ago

State and Explain the trend in the atomic radius down a group

balu736 [363]

Explanation:

<h2>The number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital.</h2>

7 0

1 year ago

IS THIS A BALANCED EQUATION <br> MgCl2 + Na2O -- > MgO + 2 NaCl

Dmitriy789 [7]

Yes, this is balanced. Each part of the substance (like Mg) has the same number on both sides.

Hope this helps you:)

8 0

3 years ago

If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?

Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

$A=Ao*exp(-kt)$

We can firstly calculate the rate constant given the half-life as shown below:

$k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}$

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

$A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g$

Regards!

5 0

3 years ago

2. A shopper in a supermarket takes a box of sugar from a shelf that is 1.5 m high because he is

muminat

Explanation:

kinetic energy?? idek hope I helped in anyway possible

7 0

3 years ago