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emmainna [20.7K]

2 years ago

13

Check all of the expressions that are equal to the one below. (-8). (4 + 6) O A. (6 + 4) • (8) B. (-8) • 4 + (-8) - 6 O C. (4+6)

• (-8) O D. (-8) • 4-(8) • 6

1 answer:

olasank [31]2 years ago

6 0

Answer:

1 is, 2 is, 3 isn't, 4 isn't

Step-by-step explanation:

Some answers may not add up the same way!

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Elodia [21]

Y-(-1)=3(x-3)->y+1=3x-9->y=3x-10 so y=3x-10 is your new line

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3 years ago

Identify the number of terms in the expression 9m+7

lara31 [8.8K]

The number of terms in the expression is 2

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3 years ago

in massaschusetts a team of scientists studying great white sharks estimate that a population of 15000 seals support fewer than

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Explanation:

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2 years ago

Which situation could be modeled by the expression 3/4 ÷ 2 1/4?

vlabodo [156]

Answer:

$\frac{1}{3}$

Step-by-step explanation:

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3 years ago

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

3 years ago