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lisov135 [29]
3 years ago
12

Which is a zero of the quadratic function f(x) = 4x2 + 24x + 11?

Mathematics
2 answers:
Alina [70]3 years ago
6 0
I answered this a few minutes ago
Ket [755]3 years ago
3 0

B. x = -5.5 is right hopefully


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Solve (x + 2) (x + 3) + (x – 3) (x – 2) – 2x(x + 1) = 0<br> x = 5<br> x = 6<br> x = 7<br> x = 8
Anna11 [10]

Answer:

x = 6

Step-by-step explanation:

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Please Help and please show the math on how you go the answer
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Step-by-step explanation:

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What is the best measure of center for this data?
brilliants [131]

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3 years ago
An architect creates a blieprint of 1inch=3.5ft if the actual length of a patio is 21 feet how long will the patios length appea
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Step-by-step explanation:

8 0
3 years ago
10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend
ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

                            =18 +16+14+12+10+8+6+4+2

                            = 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

   =6 +4

   =10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

   =6 +4

   =10

Hence proved.

3 0
3 years ago
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