Lead(II) nitrate will react with iron(III) chloride to produce the precipitate lead(II) chloride as shown in the balanced reaction
2FeCl3(aq) + 3Pb(NO3)2(aq) → 2Fe(NO3)3(aq) + 3PbCl2(s)
Calculating the amount of the precipitate lead(II) chloride each reactant will produce:
mol PbCl2 = 0.050L Pb(NO3)2 (0.100mol/1L)(3mol PbCl2/3mol Pb(NO3)2)
= 0.00500mol PbCl2
mol PbCl2 = 0.050L FeCl3 (0.100mol FeCl3/1L)(3mol PbCl2/2mol FeCl3) = 0.00750mol PbCl2
The reactant Pb(NO3)2 produces a lesser amount of the precipitate PbCl2, therefore, the lead(II) nitrate is the limiting reagent for this reaction.
Answer:
so the order is grass, which gets eaten by the grasshopper, which is eaten by the frog, which gets eaten by the snake. grass wpuld be at top, snake at bottom.
Explanation:
hope this helps
PV = nRTP is pressure, V is volume in L, n is number of moles, R is the gas constant,and T is temperature in K
(1.5 atm)(1 L) = (n)(.08206)(301K)
n = .06 moles in one liter
If there are 3.9 grams in .06 moles then
1/.06 x 3.9 = 64.2 grams per mol
Answer:
Appearing disoriented, such as swimming upside down.
Leaving food uneaten.
White spots on fins or body.
Discolored gills.
Explanation:
Gold Fish are unable to regulate their body temperature, so they are influenced by the temperature around them. If the water is warm, gold fish metabolism accelerates, feeding and respiration increases, and there is a general increase in movement. If the water is cooler, fish become lethargic and tend to be inactive.
