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3 years ago

When a simple machine multiplies force, it decreases

1 answer:

7 0

When a simple machine multiplies force, it decreases (B) Distance moved, force is described as an interaction, which, unopposed, will change the motion of an object, the potential energy, however, remains the same.

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A bicycle wheel is mounted on a fixed, frictionless axle, with a light string wound around its rim. The wheel has moment of iner

Stells [14]

Answer:

Explanation:

trying to find the inetria magnitude of the wheel

3 0

3 years ago

In an electromagnet, what produces the magnetic field?

ziro4ka [17]

C good luck ok good luck with

3 0

3 years ago

The total sum of atoms in an object.

Darina [25.2K]

Answer:

Mass

Explanation:

The total sum of atoms in an object is the mass of the object. There are several ways to quantify the number of atoms in a substance.

In chemical calculations, the number of moles is a good representation of the number of atoms contained in a body.
Mass is the amount of substances a body has.
If we can sum up all the atoms in a substance, one will arrive at the mass of the substance

4 0

3 years ago

Si un planeta tuviese un periodo de traslación de 65 años terrestres a que distancia se encontraría del sol

Tju [1.3M]

Answer:

$R \approx 2.418\times 10^{9}\,km$

Explanation:

(The following exercise is written in Spanish and for that reason explanation will be held in Spanish)

Supóngase que el planeta tiene una órbita circular, el período de rotación del planeta es:

$T = \frac{2\pi}{\omega}$

Asimismo, la rapidez angular se describe como función de la aceleración centrípeta:

$\omega = \sqrt{\frac{a_{r}}{R} }$

Ahora se reemplaza en la ecuación de período:

$T = 2\pi \cdot \sqrt{\frac{R}{a_{r}} }$

La aceleración experimentada por el planeta es:

$a_{r} = G\cdot \frac{M_{sun}}{R^{2}}$

Se reemplaza en la ecuación de período:

$T = 2\pi \cdot \sqrt{\frac{R^{3}}{G\cdot M_{sun}} }$

La distancia del planeta con respecto al sol es finalmente despejada:

$R^{3} = G\cdot M_{sun}\cdot \left(\frac{T}{2\pi} \right)^{2}$

$R = \sqrt[3]{G\cdot M_{sun}\cdot \left(\frac{T}{2\pi} \right)^{2}}$

Finalmente, se sustituyen las variables y se determina la distancia:

$R = \sqrt[3]{\left(6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (1.989\times 10^{30}\,kg)\cdot \left[\frac{(65\,a)\cdot \left(365\,\frac{d}{a} \right)\cdot \left(86400\,\frac{s}{d} \right)}{2\pi} \right]^{2}}$

$R \approx 2.418\times 10^{12}\,m$

$R \approx 2.418\times 10^{9}\,km$

4 0

3 years ago

The process of evaluating evidence to form an attitude is called

tatyana61 [14]

The process of evaluating evidence to form an attitude should be called Cognitive evaluation.

5 0

3 years ago