The acceleration is equal to force divided by mass which would be 100 / 50 which is 2 m/s2
Answer:
0.387 g
Explanation:
pH of the buffer = 1
V = Volume of solution = 100 mL
[HA] = Molarity of HA = 0.1 M
= Acid dissociation constant =
(assuming base as
)
Molar mass of base = 322.2 g/mol
pKa is given by

From the Henderson-Hasselbalch equation we get
![pH=pK_a+\log\dfrac{[A^-]}{[HA]}\\\Rightarrow pH-pK_a=\log\dfrac{[A^-]}{[HA]}\\\Rightarrow 10^{pH-pK_a}=\dfrac{[A^-]}{[HA]}\\\Rightarrow [A^-]=10^{pH-pK_a}[HA]\\\Rightarrow [A^-]=10^{1-1.92}\times0.1\\\Rightarrow [A^-]=0.01202\ \text{M}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%20pH-pK_a%3D%5Clog%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%2010%5E%7BpH-pK_a%7D%3D%5Cdfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D10%5E%7BpH-pK_a%7D%5BHA%5D%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D10%5E%7B1-1.92%7D%5Ctimes0.1%5C%5C%5CRightarrow%20%5BA%5E-%5D%3D0.01202%5C%20%5Ctext%7BM%7D)
Moles of base

Mass of base is given by

The required mass of the base is 0.387 g.
Umm what kind of question is that but i think gain lol
Answer:
Explanation:(1)base are slippery to touch e.g sodium hydroxide NaOH(aq)..
(2) They can be corrosive e.g pottasium hydroxide KOH(aq) and sodium hydroxide NOH(aq)
(3) They can act as electrolytes e.g NaOH(aq)
(4) they react to acids to form salt and water
Na0H(s)+HCL(aq)>>>NaCL(a)+H20(l)
(5)they dissolve in water to form hydroxyl ion
KoH(aq) >>>>>k+ + 0H-