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ahrayia [7]
3 years ago
9

When a phasor-domain circuit has dependent sources, you should not use a sequence of source transforms to find the thévenin and

norton equivalents for that circuit, and you cannot use the equivalent impedance technique to find the equivalent impedance. instead, you must find the open-circuit phasor voltage (which is the thévenin voltage) and the short-circuit phasor current (which is the norton current). then you can use ohm's law with the phasor voltage and current to find the thévenin (or norton) impedance. remember that you can also use the test source method to find the thévenin impedance. consider the circuit shown here. in this circuit, the phasor voltage source vs=10∠0∘ v. we wish to find the norton equivalent of this circuit to the left of terminals a and
b?
Chemistry
1 answer:
Ierofanga [76]3 years ago
4 0
Yes but the answer is A

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DaniilM [7]

Answer:

∴ΔH₂ = - 12,258 KJ

Explanation:

Enthalpy:

Enthalpy is a property of a thermodynamic system. Enthalpy of a system is equal to the sum of internal energy of the system and presser times volume of the system.

    The heat absorbes or releases in a closed system is the change of enthalpy of the system.

Given reactions are:

Reaction 1: C₃H₈(g)+5O₂(g)→ 3CO₂(g)+4H₂O,                 ΔH₁= - 2043 KJ

Reaction 2: 6C₃H₈(g)+30 O₂(g)→ 18 CO₂(g)+24 H₂O,     ΔH₂=?

Take a look at reaction 1 and reaction 2, the only difference is that 1 molecule of C₃H₈ is combusted in reaction 1 and 6 molecules of C₃H₈  is  combusted in reaction 2.

We can think the reaction 2 as occurring 6 different container and each containers contains 1 molecule of C₃H₈. The enthalpy is an extensive property. Total enthapy of the 6 containers is = 6×(-2043 KJ)

                                                                            = - 12,258 KJ

∴ΔH₂ = - 12,258 KJ

6 0
3 years ago
How does water’s ability to form hydrogen bonds explain why ice is less dense than liquid water?
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Answer:

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Explanation:

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MrRissso [65]
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Answer:

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Explanation:

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When electron jump into lower energy level from high energy level it loses the energy.

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De-excitation:

When the excited electron fall back to the lower energy levels the energy is released in the form of radiations. this energy is exactly equal to the energy difference between the orbits. The characteristics bright colors are due to the these emitted radiations. These emitted radiations can be seen if they are fall in the visible region of spectrum.

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