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ahrayia [7]
3 years ago
9

When a phasor-domain circuit has dependent sources, you should not use a sequence of source transforms to find the thévenin and

norton equivalents for that circuit, and you cannot use the equivalent impedance technique to find the equivalent impedance. instead, you must find the open-circuit phasor voltage (which is the thévenin voltage) and the short-circuit phasor current (which is the norton current). then you can use ohm's law with the phasor voltage and current to find the thévenin (or norton) impedance. remember that you can also use the test source method to find the thévenin impedance. consider the circuit shown here. in this circuit, the phasor voltage source vs=10∠0∘ v. we wish to find the norton equivalent of this circuit to the left of terminals a and
b?
Chemistry
1 answer:
Ierofanga [76]3 years ago
4 0
Yes but the answer is A

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A molecule of antifreeze, ethylene glycol, has the formula c2h4(oh)2. how many atoms are there in one molecule of antifreeze?
kifflom [539]
Answer is: there are ten atoms in one molecule of antifreeze.
One molecule of ethylene glycol (C₂H₄(OH)₂) has two carbon atoms, six hydrogen atoms (4 + 2 · 1) and two oxygen atoms (2 · 1). So there are:
2 + 6 + 2 = 10 atoms.
Ethylene glycol (C₂H₄(OH)₂) is an odorless, sweet-tasting, colorless viscous liquid.
5 0
3 years ago
Read 2 more answers
Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

8 0
3 years ago
3) Explain the difference between CO2 and C204.
kkurt [141]

Answer:

CO2 consists of one carbon atom and 2 oxygen atoms, where as C2O4 consists of 2 carbon atoms and 4 oxygen atoms. CO2 has a ration of one carbon atom to every 2 oxygen atoms and C2O4 has a ratio of 1:2 aswell

Explanation:

5 0
4 years ago
Read 2 more answers
Please help me with this question
Tcecarenko [31]

Answer:

Moon

Explanation:

5 0
3 years ago
What is the pOH of a 3.0 x10-3 M NaOH solution?<br> pOH =
kodGreya [7K]

Answer:

2.5

Explanation:

From the question given above, the following data were obtained:

Molarity of NaOH = 3.0x10¯³ M

pOH =?

Next, we shall determine the concentration of the hydroxide ion in the solution. This can be obtained as follow:

NaOH (aq) —> Na⁺ (aq) + OH¯ (aq)

From the balanced equation above,

1 mole of NaOH produced 1 mole of OH¯.

Therefore, 3.0x10¯³ M NaOH will also produce 3.0x10¯³ M OH¯.

Finally, we shall determine the pOH of the solution. This can be obtained as illustrated below:

Concentration of hydroxide ion [OH¯] = 3.0x10¯³ M

pOH =?

pOH = – Log [OH¯]

pOH = – Log 3.0x10¯³

pOH = 2.5

Thus, the pOH of the solution is 2.5

4 0
3 years ago
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