Answer is: there are ten atoms in one molecule of antifreeze.
One molecule of ethylene glycol (C₂H₄(OH)₂) has two carbon atoms, six hydrogen atoms (4 + 2 · 1) and two oxygen atoms (2 · 1). So there are:
2 + 6 + 2 = 10 atoms.
Ethylene glycol (C₂H₄(OH)₂) is an odorless, sweet-tasting, colorless viscous liquid.
Answer:
0.0159m
Explanation:
9 M
Explanation:
Lead(II) chloride,
PbCl
2
, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.
Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,
K
sp
, will be established between the solid lead(II) chloride and the dissolved ions.
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
Now, the molar solubility of the compound,
s
, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.
Notice that every mole of lead(II) chloride will produce
1
mole of lead(II) cations and
2
moles of chloride anions. Use an ICE table to find the molar solubility of the solid
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
I
−
0
0
C
x
−
(+s)
(
+
2
s
)
E
x
−
s
2
s
By definition, the solubility product constant will be equal to
K
sp
=
[
Pb
2
+
]
⋅
[
Cl
−
]
2
K
sp
=
s
⋅
(
2
s
)
2
=
s
3
This means that the molar solubility of lead(II) chloride will be
4
s
3
=
1.6
⋅
10
−
5
⇒
s
= √
1.6
4
⋅
10
−
5 =
0.0159 M
Answer:
CO2 consists of one carbon atom and 2 oxygen atoms, where as C2O4 consists of 2 carbon atoms and 4 oxygen atoms. CO2 has a ration of one carbon atom to every 2 oxygen atoms and C2O4 has a ratio of 1:2 aswell
Explanation:
Answer:
2.5
Explanation:
From the question given above, the following data were obtained:
Molarity of NaOH = 3.0x10¯³ M
pOH =?
Next, we shall determine the concentration of the hydroxide ion in the solution. This can be obtained as follow:
NaOH (aq) —> Na⁺ (aq) + OH¯ (aq)
From the balanced equation above,
1 mole of NaOH produced 1 mole of OH¯.
Therefore, 3.0x10¯³ M NaOH will also produce 3.0x10¯³ M OH¯.
Finally, we shall determine the pOH of the solution. This can be obtained as illustrated below:
Concentration of hydroxide ion [OH¯] = 3.0x10¯³ M
pOH =?
pOH = – Log [OH¯]
pOH = – Log 3.0x10¯³
pOH = 2.5
Thus, the pOH of the solution is 2.5