The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
The remainder is 23.
105 R23
Answer:
the answer is -5x + -8x-5/2x^2-3
Step-by-step explanation:
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