An electron has the properties of a _____ and _____

1. Does the temperature rise or drop when you mix vinegar and baking soda.

Viktor [21]

Answer:

Yes

Explanation:

In a chemical reaction heat is produced as a result of the reaction

3 0

3 years ago

4. Salt and water are stirred together in a beaker. The solid salt particles seem to disappear

mote1985 [20]

Answer:

I think C. A compound has been created

4 0

3 years ago

How much heat, in kJ, is required to raise the temperature of 50 g of water by 5.53°C? (Round to the nearest 10 kJ, and enter on

Triss [41]

Answer:

$Q=1.16kJ$

Explanation:

Hello,

in this case, the required heat to increase the water by 5.53 °C is computed by using the mass, heat capacity and change in temperature during the process:

$Q=mCp\Delta T$

Thus, for the given data we compute it in kJ:

$Q=50g*4.186\frac{J}{g*\°C}*(5.53\°C)*\frac{1kJ}{1000J} \\\\Q=1.16kJ$

Best regards.

5 0

3 years ago

How many moles are there in a 1.80 kg bottle of water?

yuradex [85]

Moles=mass/molar mass of water. the molar mass of water is found to be 18g which is calculated adding the molar mass of hydrogen plus that of oxygen that is(2x 16)+(1 x2)=18g/mol
convert Kg to grams that is 1.8kg x 1000=1800g

moles is therefore 1800g /18g/mol=100 mol

6 0

3 years ago

CaCO3(s) ∆→CaO(s) + CO2(g).

sveta [45]

Answer:

74.9%.

Explanation:

Relative atomic mass data from a modern periodic table:

Ca: 40.078;
C: 12.011;
O: 15.999.

What's the <em>theoretical</em> yield of this reaction?

In other words, what's the mass of the CO₂ that should come out of heating 40.1 grams of CaCO₃?

Molar mass of CaCO₃:

$M(\text{CaCO}_3) = 40.078 + 12.011 + 3 \times 15.999 = 100.086\;\text{g}\cdot\text{mol}^{-1}$ .

Number of moles of CaCO₃ available:

$\displaystyle n(\text{CaCO}_3) =\frac{m}{M} = \frac{40.1}{100.086} = 0.400655\;\text{mol}$ .

Look at the chemical equation. The coefficient in front of both CaCO₃ and CO₂ is one. Decomposing every mole of CaCO₃ should produce one mole of CO₂.

$n(\text{CO}2) = n(\text{CaCO}_3)= 0.400655\;\text{mol}$ .

Molar mass of CO₂:

$M(\text{CO}_2) = 12.011 + 2\times 15.999 = 44.009\;\text{g}\cdot\text{mol}^{-1}$ .

Mass of the 0.400655 moles of $\text{CO}_2$ expected for the 40.1 grams of CaCO₃:

$m(\text{CO}_2) = n\cdot M = 0.400655 \times 44.009 = 17.632\;\text{g}$ .

What's the <em>percentage</em> yield of this reaction?

$\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%$ .

7 0

3 years ago

An electron has the properties of a _____ and ______

An electron has the properties of a _ and __