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Daniel [21]
3 years ago
10

The gas in a 350 mL balloon has a pressure of 0.85 atm. If the temperature remains constant, what will be the pressure of the ga

s in the balloon if the volume increases to 450 mL?
Chemistry
1 answer:
Lina20 [59]3 years ago
8 0

Answer:

<h2>0.66 atm </h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

We have

P_2  =  \frac{350 \times 0.85}{450}  =  \frac{297.5}{450}  \\  = 0.661111...

We have the final answer as

<h3>0.66 atm</h3>

Hope this helps you

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Charles Law is a given volume mass of gas varies directly with the kelvin temperatures when the volume remains constant.

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Hope that helps!!!
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4 years ago
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
tino4ka555 [31]

Answer:

2.1 × 10⁻¹ M

2.0 × 10⁻¹ m

Explanation:

Molarity

The molar mass of aniline (solute) is 93.13 g/mol. The moles corresponding to 3.9 g are:

3.9 g × (1 mol/93.13 g) = 0.042 mol

The volume of the solution is 200 mL (0.200 L). The molarity of aniline is:

M = 0.042 mol/0.200 L = 0.21 M = 2.1 × 10⁻¹ M

Molality

The moles of solute are 0.042 mol.

The density of the solvent is 1.05 g/mL. The mass corresponding to 200 mL is:

200 mL × 1.05 g/mL = 210 g = 0.210 kg

The molality of aniline is:

m = 0.042 mol/0.210 kg = 0.20 m = 2.0 × 10⁻¹ m

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Calculate the pH of a buffer solution prepared by mixing 75.0 mL of 1.00 M lactic acid and 25.0 mL of 0.50 M sodium lactate.
max2010maxim [7]

From the calculations, the pH of the buffer is 3.1.

<h3>What is the pH of the buffer solution?</h3>

The  Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;

pH = pKa + log[(salt/acid]

Amount of the salt = 25/1000 *  0.50 M = 0.0125 moles

Amount of the acid = 75/1000 *  1.00 M = 0.075 moles

Total volume = ( 25 + 75)/1000 = 0.1 L

Molarity of salt = 0.0125 moles/0.1 L = 0.125 M

Molarity of the acid = 0.075 moles/0.1 L = 0.75 M

Given that the pKa of lactic acid is 3.86

pH = 3.86 + log( 0.125/0.75)

pH = 3.1

Learn more about pH:brainly.com/question/5102027

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