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3 years ago

Someone help ,, I'll give brainliest lolll .

Chemistry

1 answer:

Margaret [11]3 years ago

5 0

Answer:

Explanation:

Corrosion is a natural process that converts a refined metal into a more chemically stable form . It is the gradual destruction of materials by chemical

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At a certain concentration of H2 and I2, the initial rate of reaction is 4.0 x 104 M / s. What would the initial rate of the rea

andreev551 [17]

The question is incomplete, here is the complete question:

The rate of certain reaction is given by the following rate law:

$rate=k[H_2]^2[I_2]^2$

At a certain concentration of $H_2$ and $I_2$ , the initial rate of reaction is 4.0 × 10⁴ M/s. What would the initial rate of the reaction be if the concentration of

Answer : The initial rate of the reaction will be, $1.0\times 10^4M/s$

Explanation :

Rate law expression for the reaction:

$rate=k[H_2]^2[I_2]^2$

As we are given that:

Initial rate = 4.0 × 10⁴ M/s

Expression for rate law for first observation:

$4.0\times 10^4=k[H_2]^2[I_2]^2$ ....(1)

Expression for rate law for second observation:

$R=k(\frac{[H_2]}{2})^2[I_2]^2$ ....(2)

Dividing 2 by 1, we get:

$\frac{R}{4.0\times 10^4}=\frac{k(\frac{[H_2]}{2})^2[I_2]^2}{k[H_2]^2[I_2]^2}$

$\frac{R}{4.0\times 10^4}=\frac{1}{4}$

$R=1.0\times 10^4M/s$

Therefore, the initial rate of the reaction will be, $1.0\times 10^4M/s$

4 0

3 years ago

Acid/base, precipitation, redox, or none:. 1. Ba(ClO3)2(s) ----> BaCl2(s) + 3O2(g). 2. CaO(s) +CO2(g) ----> CaCO3(s)

Aleks04 [339]

There are two equations given in the question. The type of reaction shown can be easily judged, if one takes a closer look at the equations.

1. Ba(ClO3)2(s) ----> BaCl2(s) + 3O2(g) ------- Redox

2. CaO(s) +CO2(g) ----> CaCO3(s) -------- None.

I hope that this is the answer that you were looking for and the answer has actually come to your desired help.

4 0

3 years ago

Hydrocyanic acid is a weak acid. Therefore, the salt KCN is

Step2247 [10]

It is basic because of the fact that it has a strong base which is KOH and a weak acid HCN and the strong base causes it to remain more basic.

8 0

3 years ago

vanadium has an atomic mass of 50.9415 amu. it has two common isotopes.one isotopes has a mass of 50.9440 amu and a relative abu

Kaylis [27]

Explanation:

Average atomic mass of the vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

Average atomic mass of vanadium =

m × abundance of isotope(I) + m' × abundance of isotope (II)

50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025

m'= 49.944 amu

The atomic mass of isotope (II) of vanadium is 49.944 amu.

5 0

3 years ago

When 0.110 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are pro

olganol [36]

0.11 moles of Aluminium chloride

Explanation:

Given:

2Al + 3Cl₂ → 2AlCl₃

According to the balanced equation:

2 moles pf Aluminium form 2 moles of Aluminium chloride.

So, 1 mole of Al will form 1 mole of Aluminium chloride.

0.11 mole of Al is present.

So, 0.11 mol of Al will form 0.11 mol of Aluminium chloride.

6 0

4 years ago