Linear because x moves up by 3 and y moves up by 7
Answer:
the anwser is y=5600
I'm going to just go by this because of research and you didn't show the 4 problems so if this fixes your question then there you go
If perimeter is 60 so the side is 60 ÷ 3 = 20
Now we can apply the area formula for triangles;
The function you seek to minimize is
()=3‾√4(3)2+(13−4)2
f
(
x
)
=
3
4
(
x
3
)
2
+
(
13
−
x
4
)
2
Then
′()=3‾√18−13−8=(3‾√18+18)−138
f
′
(
x
)
=
3
x
18
−
13
−
x
8
=
(
3
18
+
1
8
)
x
−
13
8
Note that ″()>0
f
″
(
x
)
>
0
so that the critical point at ′()=0
f
′
(
x
)
=
0
will be a minimum. The critical point is at
=1179+43‾√≈7.345m
x
=
117
9
+
4
3
≈
7.345
m
So that the amount used for the square will be 13−
13
−
x
, or
13−=524+33‾√≈5.655m
Answer:
Step-by-step explanation:
<u>The line x = 3 is parallel to y- axis, the perpendicular line is going to be parallel to x- axis and will have an equation:</u>
<u>Since it passes through the point (-2, 5), it will have a = 5:</u>
- y = 5 is the line we need