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Rom4ik [11]
3 years ago
15

Ohm's law states that the current (I) in amps equals the voltage (E) in volts decided by the resistance (R) in ohm's. If you con

nected a 2 megohm resistor (2•10^6 ohms)across a 2.4 kilovolt voltage source (2.4•10^3 volts ) , what would be the currents amps ?
Engineering
1 answer:
Hitman42 [59]3 years ago
7 0

Answer:

1.14 * 10^-3  amperes

Explanation:

According to ohms law

V = IR   ---- ( 1 )

V = voltage  = 2.4 * 10^3 v

I = current  = ?

R = resistance =  2.1 * 10^6 Ω

from equation 1

I = V / R

 = ( 2.4 * 10^3 ) / (2.1 * 10^6 )

 = 1.14 * 10^-3  amperes

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2 years ago
A 15-ft beam weighing 570 lb is lowered by means of two cables unwinding from overhead cranes. As the beam approaches the ground
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I. Tension (cable A) ≈ 6939 lbf

II. Tension (cable B) ≈ 17199 lbf

Explanation:

Let's begin by listing out the data that we were given:

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g = 32.17405 ft/s²

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Mathematically represented thus:

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T = tension, m = mass, g = gravitational force,

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