Answer:
the pressure reading when connected a pressure gauge is 543.44 kPa
Explanation:
Given data
tank volume (V) = 400 L i.e 0.4 m³
temperature (T) = 25°C i.e. 25°C + 273 = 298 K
air mass (m) = 3 kg
atmospheric pressure = 98 kPa
To find out
pressure reading
Solution
we have find out pressure reading by gauge pressure
i.e. gauge pressure = absolute pressure - atmospheric pressure
first we find absolute pressure (p) by the ideal gas condition
i.e pV = mRT
p = mRT / V
p = ( 3 × 0.287 × 298 ) / 0.4
p = 641.44 kPa
so
gauge pressure = absolute pressure - atmospheric pressure
gauge pressure = 641.44 - 98
gauge pressure = 543.44 kPa
Answer:

Explanation:
z = number of atoms
M = Molar mass of zirconium
N = Avogadro’s number
Vc = volume of zirconium unit cell
d = density

z = 6 atoms per unit cell
M = 91.224 g/mol
N = 
d = 




Answer:
Professional engineering license
Bachelor's degree
Computer science classes
job recommendations
Answer:
When the imposter is sus : O
Explanation:
Answer:
Could ask a family member to help
Explanation: