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2 years ago

Which of the following variables are conserved?

Physics

1 answer:

olganol [36]2 years ago

8 0

Answer: C

Explanation:

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Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball

Likurg_2 [28]

Answer:

k = 4422.35 KN/m

Explanation:

Given that

Frequency ,f= 29 Hz

m = 7.5 g

Natural frequency ω

ω = 2 π f

We also know that for spring mass system

ω ² m =k

k=Spring constant

So we can say that

( 2 π f)² = m k

By putting the values

(2 x π x 29)² = 7.5 x 10⁻³ k

33167.69 = 7.5 x 10⁻³ k

k=4422.35 x 10³ N/m

k = 4422.35 KN/m

Therefore spring constant will be 4422.35 KN/m

4 0

3 years ago

Answer it answer it answer it

scoray [572]

Answer: I believe the answer is C. Higher Volume.

Explanation: I apologize if I am incorrect.

4 0

3 years ago

A 0.300 kg block is pressed against a spring with a spring constant of 8050 N/m until the spring is compressed by 6.00 cm. When

natita [175]

Answer:

a) $\mu_{k} = 0.704$ , b) $R = 0.312\,m$

Explanation:

a) The minimum coeffcient of friction is computed by the following expression derived from the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \mu_{k}\cdot m\cdot g \cdot \Delta s$

$\mu_{k} = \frac{k\cdot x^{2}}{2\cdot m\cdot g \cdot \Delta s}$

$\mu_{k} = \frac{\left(8050\,\frac{N}{m} \right)\cdot (0.06\,m)^{2}}{2\cdot (0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (7\,m)}$

$\mu_{k} = 0.704$

b) The speed of the block is determined by using the Principle of Energy Conservation:

$\frac{1}{2}\cdot k \cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}$

$v = x\cdot \sqrt{\frac{k}{m} }$

$v = (0.06\,m)\cdot \sqrt{\frac{8050\,\frac{N}{m} }{0.3\,kg} }$

$v \approx 9.829\,\frac{m}{s}$

The radius of the circular loop is:

$\Sigma F_{r} = -90\,N -(0.3\,kg)\cdot (9.807\,\frac{m}{s^{2}} ) = -(0.3\,kg)\cdot \frac{v^{2}}{R}$

$\frac{\left(9.829\,\frac{m}{s}\right)^{2}}{R} = 309.807\,\frac{m}{s^{2}}$

$R = 0.312\,m$

5 0

3 years ago

You want to create a device to warm food that is safe. Which type of electromagnetic wave would be most useful to investigate?

Studentka2010 [4]

The answer is Infrared waves

6 0

3 years ago

You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo

Advocard [28]

Answer:

laser's wavelength λ = 597.4 nm

Explanation:

Given:

Slit spacing, d = 1.17mm

Tenth bright fringe y = 4.57cm

Distance from slits, D = 8.95m

n = 10

λ = (d * y) / (D * n)

λ = (1.17x10⁻³ * 4.57x10⁻²) / (8.95 x 10)

λ = 5.3469‬x10⁻⁵ / 8.95x10¹

λ = 0.5974 x 10⁻⁵⁻¹

λ = 0.5974 x 10⁻⁶ m

λ = 597.4 x 10⁻⁹ m

λ = 597.4 nm

6 0

3 years ago