A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve
2 answers:
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Answer:
The amplitude of the subsequent oscillations is 13.3 cm
Explanation:
Given;
mass of the block, m = 1.25 kg
spring constant, k = 17 N/m
speed of the block, v = 49 cm/s = 0.49 m/s
To determine the amplitude of the oscillation.
Apply the principle of conservation of energy;
maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced
Therefore, the amplitude of the subsequent oscillations is 13.3 cm
The man can survive, and he lands 12.1 m from the base of the cliff (into the lake)
Explanation:
The motion of the person is equivalent to the motion of a projectile, which consists of two separate motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
We start by analyzing the vertical motion, to find the time it take for the person to reach the ground level. We can use the following suvat equation:
where
s = 50 m is the vertical distance covered (the height of the cliff)
u = 0 is the initial vertical velocity
is the acceleration of gravity
t is the time of flight
Solving for t,
The person moved horizontally at a constant speed of
So, the horizontal distance covered by the man during his flight will be
So, the man will land on the lake (which starts from 12 m), so he can survive.
Learn more about projectile motion:
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