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Alisiya [41]
2 years ago
5

A car begins at rest (0 velocity), 5 seconds later it is travelling at 20 meters/per second. What was the acceleration of the ve

hicle during these 5 seconds
Please help ASAP
Physics
2 answers:
klasskru [66]2 years ago
4 0

use the formula

v= u+ at

v is final velocity , u is initial velocity , a is acceleration and t is time

put the values

20 = 0+ a×5

a = 4 m/s²

Marta_Voda [28]2 years ago
3 0

Answer:

Initial velocity(u)=0

Final velocity(v) =20 meters/ second

Time(t)=5

Acceleration (a)=?

a=v-u/t

a=20-0/5

a=20/5

a=4meters/second

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astra-53 [7]

Answer:

D. provide the most compelling evidence of cause-and-effect relationships.

Explanation:

3 0
3 years ago
A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap
viktelen [127]

Answer:

q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}

at t = 0.001 we have

q = 1.55 \times 10^{-6} C

at t = 0.01

q = 2.99 \times 10^{-6} C

at t = infinity

q = 3 \times 10^{-6} C

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

V_r + V_L + V_c = V_{net}

now we will have

iR + L\frac{di}{dt} + \frac{q}{C} = 12 V

now we have

1\frac{d^2q}{dt^2} + (5 \times 10^3) \frac{dq}{dt} + \frac{q}{0.25 \times 10^{-6}} = 12

So we will have

q = 3\times 10^{-6} + c_1 e^{-4000 t} + c_2 e^{-1000 t}

at t = 0 we have

q = 0

0 = 3\times 10^{-6} + c_1  + c_2

also we know that

at t = 0 i = 0

0 = -4000 c_1 - 1000c_2

c_2 = -4c_1

c_1 = 1 \times 10^{-6}

c_2 = -4 \times 10^{-6}

so we have

q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}

at t = 0.001 we have

q = 1.55 \times 10^{-6} C

at t = 0.01

q = 2.99 \times 10^{-6} C

at t = infinity

q = 3 \times 10^{-6} C

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3 years ago
Why does heat cause a substance to expand?
natita [175]
Middle school? lol but, the third one.
5 0
3 years ago
A 927 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless trac
liraira [26]

Answer:

2.7 s

Explanation:

The period of the motion of a massless loaded spring is given by

T = 2\pi\sqrt{\dfrac{m}{k}}

where m is the mass of the load and k is the force or spring constant.

Using values in the question and converting to appropriate units,

T = 2\pi\sqrt{\dfrac{927\times10^{-3}\text{ kg}}{5 \text{ N/m}}}= 2.7\text{ s}

5 0
3 years ago
Read 2 more answers
1. A skier takes off from the top of the ski run and
vampirchik [111]

Answer:

a = 6 [m/s^2]

Explanation:

In order to calculate the acceleration of the skier, the following expression of kinematics must be used:

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a = 24/4 = 6 [m/s^2]

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3 years ago
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