The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.
<h3>Why is a solution of sodium sulfate used as an antidote?</h3>
The ability of sodium sulfate to act as an antidote to barium chloride poisoning is because of the reactivity of sodium.
Sodium is a more reactive metal than barium, so it displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.
The equation of the reaction is given below:
- BaCl2 + Na2SO4 ----> BaSO4 + NaCl
Therefore, the ability of sodium sulfate to act as an antidote to barium chloride poisoning is because displaces barium in barium chloride to form sodium chloride and insoluble harmless barium sulfate.
Learn more about about reactivity of metals at: brainly.com/question/24866635
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Explanation:
Answer: 6.6 ml
Explanation:
If you had a 0.200 L solution containing 0.0140 M of Fe3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.
You have 0.014X0,2 = 0,0028 moles of Fe ion.
You need 0,0028 X 3 = 00084 moles of OH
The NaOH is 1.27 moles/liter
0.084/1.27 = 6.6 ml