Answer:
The wavelength of sunlight that can cause this bond breakage is 242 nm
Explanation:
The minimum energy of the sunlight that'll break Oxygen-oxygen bond must match 495 KJ/mol
But 1 mole of any molecule contains 6.02 × 10²³ molecules/mol
Each molecule of Oxygen will require (495 × 10³)/(6.02 × 10²³) = 8.22 × 10⁻¹⁹ J
E = hf
v = fλ
f = v/λ
f = frequency of the sunlight
λ = wavelength of the sunlight
v = speed of light = 3.0 × 10⁸ m/s
E = hv/λ
λ = hv/E
h = Planck's constant = 6.63 × 10⁻³⁴ J.s
λ = (6.63 × 10⁻³⁴)(3 × 10⁸)/(8.22 × 10⁻¹⁹)
λ = 2.42 × 10⁻⁷ m = 242 nm.
Yes, electromagnetic can travel without medium.
Mechanical waves and electromagnetic waves are two important ways that energy is transported in the world around us.
Waves in water and sound waves in air are two examples of mechanical waves.
Mechanical waves are caused by a disturbance or vibration in matter, whether solid, gas, liquid, or plasma.
Matter that waves are traveling through is called a medium.
These mechanical waves travel through a medium by causing the molecules to bump into each other, like falling dominoes transferring energy from one to the next.
Sound waves cannot travel in the vacuum of space because there is no medium to transmit these mechanical waves.
On the other hand electromagnetic waves don't require medium for its propagation.
An easy example would be light which is an EM wave reaches earth even though space has no medium.
Learn more about different types of waves here:
brainly.com/question/13364787
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Answer:
Make sure everything is organized have a planner it can help
Get rid of all distractions
Listen to music if it helps you concentrate
Have your notes
Being willing to stay focus on what you are doing
Understand what you are doing
And most off all Be Happy and Remain Calm : )
Answer: Add an incline or grade to the road track.
Explanation:
Refer to the figure shown below.
When a vehicle travels on a level road in a circular path of radius r, a centrifugal force, F, tends to make the vehicle skid away from the center of the circular path.
The magnitude of the force is
F = mv²/r
where
m = mass of the vehicle
v = linear (tangential) velocity to the circular path.
The force that resists the skidding of the vehicle is provided by tractional frictional force at the tires, of magnitude
μN = μW = μmg
where
μ = dynamic coefficient of friction.
At high speeds, the frictional force will not overcome the centrifugal force, and the vehicle will skid.
When an incline of θ degrees is added to the road track, the frictional force is augmented by the component of the weight of the vehicle along the incline.
Therefore the force that opposes the centrifugal force becomes
μN + Wsinθ = W(sinθ + μ cosθ).