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3241004551 [841]
3 years ago
10

Which action(s) is/are true of antihistamines? (select all that apply.) test bank?

Chemistry
1 answer:
Sav [38]3 years ago
7 0
The correct answers from the choices are:

a. Reduce inflammation locally
b. Antagonize H1 receptors
c. May be administered orally
<span>d. Are systemically distributed

</span><span>Antihistamines are drugs that are H1 antagonists or blockers, may be administered orally, are distributed systemically, and do not directly reduce nasal congestion.</span>
You might be interested in
A box has a weight of 120 lbs and the bottom of the box is 12 in2 . What is the pressure the box exerts on the floor?
denis23 [38]
How can I help with this question?
7 0
3 years ago
Given the unbalanced equation below, answer the following: Calculate the number of liters of 3.00 M lead (II) iodide solution pr
mr_godi [17]

The number of liters of 3.00 M lead (II) iodide : 0.277 L

<h3>Further explanation</h3>

Reaction(balanced)

Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)

moles of KI = 1.66

From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :

\tt \dfrac{1}{2}\times 1.66=0.83

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):

\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.83}{3}\\\\V=0.277~L

5 0
3 years ago
60 points please help me i will appreciate it!
VARVARA [1.3K]

Answer:

This is a pretty straightforward example of how an ideal gas law problem looks like.

Your strategy here will be to use the ideal gas law to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant.

So, the ideal gas law equation looks like this

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

P

V

=

n

R

T

a

a

∣

∣

−−−−−−−−−−−−−−−

Here you have

P

- the pressure of the gas

V

- the volume it occupies

n

- the number of moles of gas

R

- the universal gas constant, usually given as

0.0821

atm

⋅

L

mol

⋅

K

T

- the absolute temperature of the gas

Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of

R

.

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Liters, L

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Liters, L

a

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Kelvin, K

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Celsius,

∘

C

a

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×

Notice that the temperature of the gas must be expressed in Kelvin in order to work, so make sure that you convert it before plugging it into the ideal gas law equation

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

T

[

K

]

=

t

[

∘

C

]

+

273.15

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−

Rearrange the ideal gas law equation to solve for

P

P

V

=

n

R

T

⇒

P

=

n

R

T

V

Plug in your values to find

P

=

0.325

moles

⋅

0.0821

atm

⋅

L

mol

⋅

K

⋅

(

35

+

273.15

)

K

4.08

L

P

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

2.0 atm

a

a

∣

∣

−−−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the temperature of the gas.

6 0
2 years ago
Read 2 more answers
To begin the experiment, 1.11g of methane CH4 is burned in a bomb calorimeter containing 1000 grams of water. The initial temper
yaroslaw [1]
In order to calculate the enthalpy of the reaction, we first calculate the heat released using the given formula.
Q = mc<span>ΔT
Q = 1000 x 4.184 x (35.65 - 24.85)
Q = 45187.2 J = 45.2 kJ

Now, we determine the moles of methane that were burned.
Moles = mass / Mr
Moles = 1.11 / (12 + 4)
Moles = 0.07

The enthalpy of a reaction is the energy released per mole, so the enthalpy in this case is:
</span>ΔH = 45.2 / 0.07
ΔH = 645.7 kJ/mol
8 0
3 years ago
The pressure in a bicycle tire is 1.34atm at 33.0 ° C. At what temperature will the pressure inside the tire be 1.60atm?
Y_Kistochka [10]

Answer:

92.37°C

Explanation:

Assuming the volume remains the same in both the states ( bicycle tire).

Then as per ideal gas equation

P_1/T_1 = P_2/T_2

where P1, P2 are pressure at two different states and T1, T2 are temperature at these two states

Given:

P1 = 1.34 atm, T1 = 33.0 ° C = 306K

P2 = 1.60 atm, T2 = ?

1.34/306 = 1.60/T_2

⇒ T2 = 1.60×306/1.34

= T2= 365.37K= 92.37°C

8 0
2 years ago
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