Answer: The moles of KIO cuboid titrated are 0.0002382
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in ml
Now put all the given values in the formula of molarity, we get
Therefore, the moles of KIO cuboid are 0.0002382
Answer:
3.0x10⁻²M
Explanation:
Silver sulfate, Ag₂SO₄, has a product constant solubility equilbrium of:
Ag₂SO₄(s) ⇄ 2Ag⁺ + SO₄²⁻
When an excess of silver sulfate is added, some Ag₂SO₄ will react producing Ag⁺ and SO₄²⁻ until reach the equilbrium determined for the formula:
ksp = 1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]
Assuming the Ag₂SO₄ that react until reach equilibrium is X, we can replace in Ksp expression:
1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]
1.4x10⁻⁵ = [2X]² [X]
1.4x10⁻⁵ = 4X³
3.5x10⁻⁶ = X³
0.015 = X
As [Ag⁺] is 2X:
[Ag⁺] = 0.030 = 3.0x10⁻²M
The answer is:
<h3>3.0x10⁻²M</h3>
Answer:
The structures are attached in file.
Hydrogen bonding and intermolecular forces is the reason for ranks allotted.
Explanation:
In determining Lewis structure, we calculate the overall number of valence electrons available for bonding. Making carbon (the least electronegative atom) the central atom in the structure, we allocate valence electrons until each atom has achieved stability.
In order of decreasing affinity to water molecules:
This is due to the fact that the 
will accept protons more readily than the bicarbonate ion, 
. Carbonic acid, 
will not accept any more protons, hence it is the least attractive to water molecule, even though soluble.
Answer:
The answer is true.
Explanation:
Hello! Let's solve this!
The answer is true.
When a crust undergoes great tension, a crack opens and the oceanic crust begins to form. As the crack enlarges, the continent is splitting. Thus an oceanic crust forms. So the oceanic crust is younger than the earth's crust.
In the given <span>phase diagram, the line segment that describes the interface between solid and vapor is A-B. The rest of the choices do not answer teh question above</span>
