Answer: -345.2 KJ
Explanation: As we know that ,dG=dH-TdS
T=25+273=298 K
dG= -356 x1000-298(-36)= -356000+10728
=-345272 j
= -345.2 KJ
Answer:the first one
Explanation:Bacteria living on the skin of frogs could save them from a deadly virus, ... With Differences in the Composition of the Skin Microbiome of a Wild
<h2>
Hey There!</h2><h2>
_____________________________________</h2><h2>
Answer:</h2><h2>
----------------------------------------------------------------------</h2><h2>
ELECTROPLATING </h2>
Electroplating the plating one metal on to the another metal, It is mostly used for preventing corrosion by using copper or chromium or decorate the object by using gold or silver plating.
__________________________________________________________
<h3>Principle:</h3>
When electricity is passed the thin layer of metal is deposited on another metal and water molecule given out as a By-Product, Thus this process works on the principle of Hydrolysis.
<h2>_____________________________________</h2><h2>QUESTION:</h2>
A) Electrolysis
B) Chromium prevents corrosion and gives the fine shining touch to the objects.
C) The metal which is deposited to the object i.e. spoon will be connected to the positive electrode of a battery, Thus it is anode. The spoon at which electroplating is need to be done is connected to the negative electrode, thus the Spoon is cathode.
<h2>
_____________________________________</h2><h2>
Best Regards,</h2><h2>
'Borz'</h2>
The balanced equation between NaOH and H₂SO₄ is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of moles of NaOH moles reacted = molarity of NaOH x volume
number of NaOH moles = 0.08964 mol/L x 27.86 x 10⁻³ L = 2.497 x 10⁻³ mol
according to molar ratio of 2:1
2 mol of NaOH reacts with 1 mol of H₂SO₄
therefore 2.497 x 10⁻³ mol of NaOH reacts with - 1/2 x 2.497 x 10⁻³ mol of H₂SO₄
number of moles of H₂SO₄ reacted - 1.249 x 10⁻³ mol
Number of H₂SO₄ moles in 34.53 mL - 1.249 x 10⁻³ mol
number of H₂SO₄ moles in 1000 mL - 1.249 x 10⁻³ mol / 34.53 x 10⁻³ L = 0.03617 mol
molarity of H₂SO₄ is 0.03617 M
