Answer:
<em>Physical activities play an important role in manage our stress levels</em>.
<u>Explanation:
</u>
In our daily life <em>we face many stressful experiences such as job, studies, a chronic disease </em>etc., <em>the brain send warnings to the muscles and to the adrenal glands which releases adrenaline and cortisol</em>. <em>Stress leads to high blood pleasure and there are many strategies to manage our stress,</em> keeping our mind in a positive attitude helps to reduce stress levels.<em> Doing physical activities keep our mind away from stress. Yoga, Meditation, Deep breathing exercises, Aerobics keeps our mind free from stress.</em>
Answer:
Hydroelectricity
Explanation:
There are varipus situations in which mechanical energy is turned into electrical energy for use but the most common is in hydroelectricity.
The attachment will give a better understanding pf how this works.
Using newton's law of gravity on a 1kg mass near the star. G is newton's grav constant. g is acceleration of grav at starGMstar/r^2 = gstar
The oscillation angular frequency of a drop with half of the first drop's radius is 4ω
<h3>What is surface tension?</h3>
Surface tension is the tension force exerted on an object by the surface of a liquid.
<h3>What is angular frequency?</h3>
Angular frequency is the frequency of oscillation of a rotating object. It is given in rad/s.
<h3>What is the oscillation angular frequency of a drop with half of the first drop's radius?</h3>
Given that
- the angular frequency of the drop is ω and
- radius r.
Since the energy of the drop is conserved, using the law of conservation of angular momentum, we have
Iω = I'ω' where
- I = initial rotational inertia of droplet = mr²
- where m = mass of drop and
- r = initial radius of droplet,
- ω = initial angular frequency of droplet,
- I' = initial rotational inertia of droplet = mr² where
- m = mass of drop and
- r' = final radius of droplet, and
- ω = final angular frequency of droplet
So, Iω = I'ω'
Making ω' subject of the formula, we have
ω' = Iω/I'
ω' = mr²ω/mr'²
ω' = r²ω/r'²
Given that the drop is half of the first drop's radius, r' = r/2
So, ω' = r²ω/r'²
ω' = r²ω/(r/2)²
ω' = r²ω/r²/4
ω' = 4ω
So, the oscillation angular frequency of a drop with half of the first drop's radius is 4ω
Learn more about angular frequency here:
brainly.com/question/28036464
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Answer:
A) True. The droplets will move in parabolic arcs.
Explanation:
When the dog shakes the drops that leave the fur they leave with a speed and an angle; These are now subject to the out of gravity that accelerates them in the vertical axis and has no outside the horizontal axis, so they must describe a parabolic movement.
Pair to describe a central force that changes its speed, but this force does not exist once they leave the dog
Let's check the answers
A) True. You agree with the analysis
B) False. There is an outside on the axis and therefore the line is deviating
C) False. There is no radial force that creates this movement
