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2 years ago

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A student squeezes a clothespin 82 times in a minute. Then, using the same hand and the same clothespin, he squeezes the clothes

pin 68 times in a minute. State one biological reason for the decrease in the number of squeezes during the second trial.

1 answer:

tia_tia [17]2 years ago

3 0

Could have gotten tired after the first trial. ? i’m not sure if that’s it

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If the magnitude of a charge is half as much as another charge, but the force experienced is the same, then the electric field s

Kazeer [188]

Answer:

the electric field strength of this charge is two times the strength of the other charge

Explanation:

Using the relationship between electric field and the charge, which is inversely proportionality. Let the the magnitude of the first charge be Q and the respective electric field be E. It implies that;

E1/E2 = Q2/Q1

E2 = E1 x Q1/Q2

= E x Q/ (Q/2)

= 2E

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2 years ago

30 points - how do I do 2 b and c?

Delvig [45]

1. its must be B and 2. must be C

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2 years ago

The earth's tectonic plates are directly propelled by the convection in the __________.

frozen [14]

The missing word here is <u>Asthenosphere.</u><u> </u>

The convection in the asthenosphere directly propels the tectonic plates of the earth.

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9 months ago

Um avião, após deslocar-se 120 km para nordeste (NE), desloca-se 160 km para sudeste (SE). Sendo um quarto de hora o tempo total

Svetach [21]

Answer:

E) 800 km/h

Explanation:

The computation of the average vector velocity module of the plane, at that time is shown below:

The displacement vector is

d^2 = d1^2 + d2^2

where,

d1 = northeast displacement

d2 = southeast displacement

Now

d^2 = (120)^2 + (160)^2

= 14400 + 2560

= 40000

= √40000

d = 200 km

Now the average velocity is

V = ΔS ÷ Δt

= 200 ÷ 1 ÷ 4

= 200 × 4

= 800 km/h

4 0

2 years ago

A particle moves along a straight line with an acceleration of a = 5>(3s 1>3 + s 5>2) m>s2, where s is in meters. De

Len [333]

Answer:

v=1.295

Explanation:

What we are given:

a=5÷(3s^(1/3)+s^(5/2)) m/s^2

Start by using equation a ds = v dv

This problem requires a numeric method of solving. Therefore, you can integrate v ds normally, but you must use a different method for a ds The problem should look like this:

$\int\limits^a_b {x} \, dx$

<em>a=2</em>

<em>b=1</em>

<em>x=5÷(3s^(1/3)+s^(5/2)) </em><em>m/s^2</em>

<em>dx=dv</em>

Integrate the left side the standard method.

$\int\limits^a_b {x} \, dx$

<em>a=v</em>

<em>b=0</em>

<em>dx=dv</em>

<em>Integrating</em>

=v^2/2

Use Simpson's rule for the right site.

$\int\limits^a_b {x} \, dx$

<em>a=b</em>

<em>b=a</em>

<em>x=f(x)</em>

f(x)=b-a/6*(f(a)+4f(a+b/2)+f(b)

If properly applied. you should now have the following equation:

v^2/2=5[(1/6*(0.25+4(0.162)+(0.106)]

=0.8376

Solve for v.

v=1.295

5 0

2 years ago