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igomit [66]
2 years ago
9

a car moves 6 km east, then 4km north. what was the distance covered? What was the total displacement?

Physics
1 answer:
Aliun [14]2 years ago
7 0

Answer:

distance= 10 km

displacement= 7.21 km

Explanation:

distance= scalar (only magnitude)

displacement= vector (magnitude & direction)

distance= 6 km+ 4 km

= 10 km

displacement= shortest difference btwn 2 pts=

sqrt( 6^2+4^2)

sqrt(52)

7.21 km

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Which of ONE of the following four elements has the most metallic properties?
olchik [2.2K]

Answer:

12 (Magnesium- Mg)

Explanation:

Looking at the four numbers, we have:

Magnesium, Silicon, Sulfur, and Chlorine.

We can eliminate two of the answers immediately just by looking at the periodic table.

Sulfur and Chlorine are on the nonmetal side of the periodic table. So that's <em>definitely</em> not it. That leaves Magnesium and Silicon.

Silicon is a Metalloid. Magnesium is an Alkaline earth Metal.

Metaloids are elements that have a mix of both<em> metal</em> and<em> nonmetal </em>properties (luster, how it feels, etc.). Since it's a MIX and Magnesium is just straight METAL-

We can say Magnesium has the most metallic properties.

hope this helps!!

7 0
3 years ago
A 2-kg toy car accelerates from 0 to 5 m/s2. It
yan [13]
10 joules of work is done by the object
8 0
2 years ago
I need help with these questions
Feliz [49]
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J

8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m

9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333


6 0
3 years ago
The spacing between the plates of a 1.0 μF capacitor is 0.050 mm. a) What is the surface area of the plates? b) How much charge
nataly862011 [7]

Answer:

(a) surface area of the plate will be equal to 1.129m^2

(b) Charge on the capacitor is equal to 1.5\times 10^{-6}C

Explanation:

We have given spacing between the plates d = 0.05 mm = 5\times 10^{-5}m

Value of capacitance C=1\mu F=10^{-6}F

(A) Capacitance of a parallel plate capacitor is equal to C=\frac{\epsilon _0A}{d}

So 10^{-6}=\frac{8.85\times 10^{-12}\times A}{10^{-5}}

A=1.129m^2

So surface area of the plate will be equal to 1.129m^2

(B) It is given that capacitor is charged by 1.5 volt

So voltage V = 1.5 volt

Charge on the capacitor is equal to Q=CV

So Q=1.5\times 10^{-6}C

5 0
3 years ago
A.Substitute in the units for each one and combine like terms.
storchak [24]
IDK     ghjfnhgfjmrmhjgfhgfmmfh
8 0
3 years ago
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