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igomit [66]
3 years ago
9

a car moves 6 km east, then 4km north. what was the distance covered? What was the total displacement?

Physics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

distance= 10 km

displacement= 7.21 km

Explanation:

distance= scalar (only magnitude)

displacement= vector (magnitude & direction)

distance= 6 km+ 4 km

= 10 km

displacement= shortest difference btwn 2 pts=

sqrt( 6^2+4^2)

sqrt(52)

7.21 km

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Answer:

Explanation:

When a force hits something, an equal amount of force is exerted back on it.

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4 years ago
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A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
hram777 [196]

Answer:

v_{2}=3.5 m/s

Explanation:

Using the conservation of energy we have:

\frac{1}{2}mv^{2}=mgh

Let's solve it for v:

v=\sqrt{2gh}

So the speed at the lowest point is v=7 m/s

Now, using the conservation of momentum we have:

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\frac{1*7}{2}

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I hope it helps you!

       

8 0
3 years ago
An old light bulb draws only 54.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what facto
Lemur [1.5K]

Answer:

The factor of the diameter is 0.95.

Explanation:

Given that,

Power of old light bulb = 54.3 W

Power = 60 W

We know that,

The resistance is inversely proportional to the diameter.

R\propto\dfrac{1}{D}

The power is inversely proportional to the resistance.

P\propto\dfrac{1}{R}

P\propto D^2

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Using relation of power and diameter

\dfrac{P_{i}}{P_{f}}=\dfrac{D_{i}^2}{D_{f}^2}

Put the value into the formula

\dfrac{D_{i}^2}{D_{f}^2}=\dfrac{54.3}{60}

\dfrac{D_{i}}{D_{f}}=0.95

D_{i}=0.95 D_{f}

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3 years ago
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Explanation:

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3 years ago
A uniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. The ladder weigh
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Answer:

Explanation:

a )

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= μ x R

= μ x 160

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= 64 N .

b )

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160 x 1.5 + 740 x 3/5 + f x 4 = 900 x 3

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c )

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x = 2.3  m

so man can go upto 2.3 at which maximum friction acts .

8 0
4 years ago
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