Answer:
a) 2CH4(g) + S8(s) → 2CS2(l) + 4H2S(g)
b) <u>4.24 moles CS2</u>
<u>c) 8.48 moles H2S</u>
Explanation:
Step 1: The unbalanced equation
CH4(g) + S8(s) → CS2(l) + H2S(g)
(a) Balance the equation. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answe.)
2CH4(g) + S8(s) → 2CS2(l) + 4H2S(g)
(b) Calculate the moles CS2 produced when 2.12 mol S8 is used.
For 2 moles CH4 we need 1 mol S8 to produce 2 moles CS2 and 4 moles H2S
For 2.12 moles S8 we'll have 2*2.12 = <u>4.24 moles CS2</u>
(c) How many moles H2S are produced?
For 2 moles CH4 we need 1 mol S8 to produce 2 moles CS2 and 4 moles H2S
For 2.12 moles S8 we'll have 4*2.12 = <u>8.48 moles H2S</u>
The chemical formula of fructose is C6H12O6
These are two questions and two answers.
Answers:
Explanation:
<u>1) Balanced chemical equation (given):</u>
- CO₂(g) + 4H₂(g) → CH₄(g) + 2H₂O(g)
<u>2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? </u>
a)<u> Mole ratios:</u>
- 1 moles CO₂(g) : 1 mole CH₄(g)
b) <u>Proportion:</u>
- 1 moles CO₂ / 1 mol CH₄ = 59.6 moles CO₂ / x
⇒ x = 59.6 mol CH₄ ← answer
<u>3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor? </u>
a) <u>Mole ratios:</u>
- 4 mol H₂(g) : 2 mol H₂O(g)
b) <u>Proportion:</u>
- 4 mol H₂ / 2 mol H₂O = x / 42.1 mol H₂O
⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer
Molecular weight of vanillin = 152 g/mol
Futher molecular formula of vanillin is C8H8O3
Atomic weight of oxygen = 16 g/mol
Thus, 152 g of vanillin contains 16 g of oxygen
∴ 0.045 g (45 mg) of vanillin contains
= 0.00473 g
Also, number of moles of vanillin in 0.045 g sample =
Now, 1 mole = 6.023 X 10^23 molecules
∴ 2.96 X 10^-4 mole = 1.78 X 10^20 molecules
From molecular formula, it can be seen that 1 molecule of vanallin contain 3 atoms of oxygen
∴1.78 X 10^20 molecules contain 3 X 1.78 X 10^20 = 5.34 X 10^20 oxygen atoms