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lawyer [7]
3 years ago
15

Explain ROLAP, and list the reasons you would recommend its use in the relational database environment.

Engineering
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

ROLAP  is a branch of OLAP that is used to contain Relational database ( RDB ). which is a very fast database ( quick process of queries )

  • Very fast to access and also fast in processing queries
  • provides multidimensional view of data / supports multidimensional database schema with RDBMs
  • supports large databases

Explanation:

ROLAP ( Relational On-line Analytical processing ) is a branch of OLAP that is used to contain Relational database ( RDB ).

<u>Advantages of ROLAP ( reasons for the use of ROLAP )</u>

  • Very fast to access ( fast in processing queries )
  • provides multidimensional view of data / supports multidimensional database schema with RDBMs
  • supports large databases

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sertanlavr [38]

Answer:

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Explanation:

6 0
3 years ago
Write a Nested While Loop that will increment the '*' from 1 to 10.
andrey2020 [161]

Answer:

The program is as follows:

i = 1

while(i<11):

   j = 1

   while(j<=i):

       print('*', end = '')

       j += 1

   i += 1

   print()

Explanation:

Initialize i to 1

i = 1

The outer loop is repeated as long as i is less than 11

while(i<11):

Initialize j to 1

   j = 1

The inner loop is repeated as long as j is less than or equal i

   while(j<=i):

This prints a *

       print('*', end = '')

This increments j and ends the inner loop

       j += 1

This increments i

   i += 1

This prints a blank and ends the inner loop

   print()

8 0
3 years ago
Im passed due someone help meeeeeee
vovangra [49]

Answer:

how are supposed to help when you can't do anything?

8 0
3 years ago
Read 2 more answers
A fluid at 300 K flows through a long, thin-walled pipe of 0.2-m diameter. The pipe is enclosed in a concrete casing that is of
andrew-mc [135]

Answer:

The correct answer is "1341.288 W/m".

Explanation:

Given that:

T₁ = 300 K

T₂ = 500 K

Diameter,

d = 0.2 m

Length,

l = 1 m

As we know,

The shape factor will be:

⇒ SF=\frac{2 \pi l}{ln[\frac{1.08 b }{d} ]}

By putting the value, we get

⇒       =\frac{2 \pi l}{ln[\frac{1.08\times 1}{0.2} ]}

⇒       =3.7258 \ l

hence,

The heat loss will be:

⇒ Q=SF\times K(T_2-T_1)

       =3.7258\times 1\times 1.8\times (500-300)

       =3.7258\times 1.8\times (200)

       =1341.288 \ W/m

3 0
3 years ago
Volume of sale (i.e., the number of parts sold) is a factorwhen determining which
nadya68 [22]

Answer: N has to be lesser than or equal to 1666.

Explanation:

Cost of parts N in FPGA = $15N

Cost of parts N in gate array = $3N + $20000

Cost of parts N in standard cell = $1N + $100000

So,

15N < 3N + 20000 lets say this is equation 1

(cost of FPGA lesser than that of gate array)

 Also. 15N < 1N + 100000  lets say this is equation 2  

(cost of FPGA lesser than that of standardcell)

Now

From equation 1

12N < 20000

N < 1666.67

From equation 2

14N < 100000

N < 7142.85

AT the same time, Both conditions must hold true

So N <= 1666 (Since N has to be an integer)

N has to be lesser than or equal to 1666.

3 0
4 years ago
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