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Kay [80]
2 years ago
15

The modifications of superheat and reheat for a vapor power plant are specifically better for the operation which of the followi

ng components. Pick one and briefly explain.
a.Condenser
b.Boiler
c.Open feedwater heater
d.Turbine
e.Electric generator
Engineering
1 answer:
MatroZZZ [7]2 years ago
7 0

The modifications of superheating and reheat for a vapor power plant are specifically better for the operation which of the following components b.Boiler.

<h3>What are the primary additives in the vapour strength cycle?</h3>

There are 5 steam strength cycles: The Carnot cycle, the easy Rankine cycle, the Rankine superheat cycle, the Rankine reheat cycle and the regenerative cycle.

  1. Central to expertise the operation of steam propulsion is the primary steam cycle, a method wherein we generate steam in a boiler, increase the steam via a turbine to extract work, condense the steam into water, and sooner or later feed the water again to the boiler.
  2. Reheat now no longer best correctly decreased the penalty of the latent warmness of vaporization in steam discharged from the low-stress quit of the turbine cycle, however, it additionally advanced the first-rate of the steam on the low-stress quit of the mills via way of means of decreasing condensation and the formation of water droplets inside the turbine.

Read more about the Boiler:

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The temperature attains equilibrium with the surroundings.  

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When the light bulb is lighted we know that it's temperature will go on increasing as the filament of the bulb has to  constantly dissipates energy during the time in which it is on. Now this energy is dissipated as heat as we know it, this heat energy is absorbed by the material of the bulb which is usually made up of glass, increasing it's temperature. Now we know that any object with temperature above absolute zero has to dissipate energy in form of radiations.

Thus we conclude that the bulb absorbs as well as dissipates it's absorbed thermal energy. we know that this rate is dependent on the temperature of the bulb thus it the temperature of the bulb does not change we can infer that an equilibrium has been reached in the above 2 processes i.e the rate of energy absorption equals the rate of energy dissipation.

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Output signal shape: square, from 0.1 to 230 MHz. Output power: -10 dBm (at a load of 50 Ohms).

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Given a mass-spring-damper system. The impulse response of strength 1 can be obtained from a unit step response by: ______
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We can obtain The impulse response of strength 1 considering a unit step response by Multiplying impulse response by t .

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