All categories

3 years ago

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution

Chemistry

1 answer:

Readme [11.4K]3 years ago

5 0

Answer:

Explanation:

no explanation sorry

You might be interested in

If the relative rate of diffusion of ozone as compared to chlorine is 6:3 and further if the density of chlorine is 36 Find out

Alexandra [31]

Answer:

The density of ozone is 4.24.

Explanation:

The relation between the relative rate of diffusion and density is given by :

$r\propto \dfrac{1}{\sqrt d}$

The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.

Let the density of ozone is d₂.

$\dfrac{r_1}{r_2}=\sqrt{\dfrac{d_2}{d_1}} \\\\\dfrac{6}{3}=\sqrt{\dfrac{d_2}{36}} \\\\3=\dfrac{\sqrt{d_2}}{6}\\\\d_2=\sqrt{18} \\\\d_2=4.24$

So, the density of ozone is 4.24.

6 0

2 years ago

Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO

zavuch27 [327]

Answer:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

$2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons 4NOBr ( g )$

The suitable equilibrium constant turns out:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Or in terms of the initial equilibrium constant:

$K_2=K_1^2$

Since the second reaction is a doubled version of the first one.

Best regards.

5 0

3 years ago

PLEASE HELP<br> two ways chemistry affects you in your daily life?

Fofino [41]

Answer:

when u do the dishes and when you take a shower i thank if you put thos in a full sentence they will be good answer

Explanation:

8 0

3 years ago

Mixtures can be separated by filtration and distillation. Both methods take advantage of ...

bagirrra123 [75]

<span>differences in the physical properties of the mixture's components</span>

5 0

3 years ago

How many molecules of CO are produced when 2.73 moles of HPO3 react? 4HPO3 + 12C ----> 2H2 + 12CO + P4

Zina [86]

According to the balanced chemical equation:
4 HPO₃ + 12 C → 2 H₂ + 12 CO + P₄
4 moles of HPO₃ ---gives---> 12 moles of CO
2.73 moles of HPO₃ ---gives---> ? moles of CO
so number of moles of CO = $\frac{(2.73 * 12)}{4}$ = 8.19 moles of CO
Number of molecules of CO = number of moles * Avogadro's number
= 8.19 * (6.022 * 10²³) = 4.93 * 10²⁴ molecules

3 0

3 years ago

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution​

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution