All categories

3 years ago

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution

Chemistry

1 answer:

Readme [11.4K]3 years ago

5 0

Answer:

Explanation:

no explanation sorry

You might be interested in

A student performs an experiment to find the percentage of water in a hydrate. He determines that the hydrate contains 22% water

Stels [109]

Answer:

A feasible error could have been the removal of the sample before all water evaporated.

Explanation:

In order to determine the percentage of water in an hydrate, an experiment that could be performed is the heating of the sample until the mass does not change. If the student heated the sample an insufficient amount of time, water will be present in the sample, thus reducing the percentage reported.

4 0

3 years ago

1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant

vodomira [7]

The masses of the components are obtained as;

Sodium hydrogen carbonate = 3.51 g
Sodium carbonate = 8.708 g

<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

$2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)$

Now, the loss in mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g - 8.708 g = 1.292 g

Mass of sodium hydrogen carbonate = 2 * 88 g/mol * 1.292 g/62 g/mol

= 3.51 g

Learn more about anhydrous sodium carbonate :brainly.com/question/20479996

#SPJ1

6 0

1 year ago

Water samples containing dissolved substances are called _____ solutions. A. solvent B. aqueous C. anhydrous D. elementary

dlinn [17]

The answer is B. hopes it help you.!!

7 0

3 years ago

A particular sample of pure iron requires 0.612 kJ of energy to raise its temperature from 30.°C to 51°C. What must be the mass

mixas84 [53]

Answer:

m = 65.637 g

Explanation:

Heat = 0.612 kJ = 612 J ( Converting to J by multiplying by 1000)

Initial Temperature = 30.°C

Final Temperature = 51°C

Temperature change = Final Temperature - Initial Temperature = 51 - 30 = 21°C

Mass = ?

The relationship between these quantities is given by the equation;

H = mCΔT

where c = 0.444 J/g°C

Inserting the values in the equation;

612 = m * 0.444 * 21

m = 612 / (0.444 * 21)

m = 65.637 g

3 0

2 years ago

Chromium-51 is a radioactive isotope used to label red blood cells to identify if they remain intact in the body. It has a half-

agasfer [191]

$\left[\begin{array}{cccc}0 \ days&27,7days&55,4days&\textbf{83,1days}\\&&&\\0,25mg&0,125mg&0,0625mg&\textbf{0,03125mg}\end{array}\right]$

5 0

3 years ago

Read 2 more answers

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution​

E is solution of HCI of unk concentration f contain 4.8g of NaOH in 25cm point of salution