Answer:
pH = 0.32
Explanation:
To solve this problem we use the <em>Henderson-Hasselbach equation</em>:
- pH = pKa + log
![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
In this case
- [A⁻] is [NH₃], as it is the conjugate base of a weak acid
- [HA] is [NH₄⁺], as it is a weak acid
So now we just <u>compute the data in the equation</u>
- pH = 9.24 + log
Answer:
The answer to the question is
The wave speed is 53.57 cm/s
Explanation:
The speed of a wave is the distance covered by the wave per unit time.
Wave speed is given by
v = f×λ
where v = The velocity of the wave
f = The wave frequency
λ = The wavelength of the wave
the speed v of the wave can also be expressed interms of the period as
v = λ/T
The freuency of the given wave is f = 5/(0.112 s) = 44.64 Hz and the wavelength is λ = 1.20 cm
Therefore the speed of the wave = 44.64 Hz × 1.20 cm = 53.57 cm/s
He proved that the mass of the products<span> in a </span>chemical reaction<span> is equal to the mass of the </span>reactants<span>. There are </span>no<span> more </span>atoms<span> at the end of the </span>chemical reaction<span> than there were at the beginning. The </span>Law of Conservation<span> of Mass states that matter can neither be created nor destroyed in a </span>chemical reaction<span>.</span>
Answer:
Explanation:
Just as context, write the chemical equation and the mole ratios
1) <u>Balanced chemical equation</u>:
- CuO (s) + H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)
2) <u>Therotetical (stoichiometric) mole ratios</u>:
- 1 mol CuO : 1 mol H₂SO₄ : 1 mol CuSO₄ : 1 mol H₂O
You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield
3) <u>Percent yield</u>
Percent yield = (actual yield / theoretical yield)×100
- Theoretical yiedl (given): 3.19 moles CuSO₄
- Actual yield (given): 2.50 moles CuSO₄
Substitute the values in the formula:
- Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%
