60\15A=help help help help help help help help help help
2 answers:
You might be interested in
The molarity of the lake water is 0.00001 M and the pH of lake water is 5.
The lake water is acidic.
Explanation:
Data given:
molarity of base solution Mbase = 0.1 M
volume of the base solution Vbase = 0.1 ml or 0.0001 litre
volume of lake water Vlake = 1000ml or 1 litre
molarity of the lake water, Mlake = ?
Using the formula for titration:
Mbase X Vbase = Mlake X
Mlake =
Putting the values in the equation:
Mlake =
Mlake = 0.00001 M
The pH of the lake water will be calculated by using the following formula:
pH = - [
]
pH = - [ 0.00001]
pH = 5
The percentage of sugar in the solution is 1%
To solve this question, we need to find the percentage of 6 out of 600.
Data given;
- mass of sugar = 6g
- mass of solution = 600g
This is the rate or proportion of a substance in the total value and multiplied by 100.
The percentage of sugar in the solution is calculated by
The percentage of sugar in the solution is 1%
Learn more about percentage here;