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3 years ago

60\15A=help help help help help help help help help help

Chemistry

2 answers:

Yuki888 [10]3 years ago

8 0

Answer:

60 divided by 15? That's 4 if that's what you're asking

ivann1987 [24]3 years ago

7 0

this is just 60 divided by 15, which is 4

so your answer is 4A :)

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NaOH (aq) + HCl(aq) H2O + NaCl (aq)

yuradex [85]

Answer:

The answer to your question is 0.005

Explanation:

Data

Volume of NaOH = 25 ml

[NaOH] = 0.2 M

moles of NaOH = ?

To solve this problem is not necessary to have the chemical reaction. Just use the formula of Molarity and solve it for moles.

Formula

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Convert volume to liters

1000 ml ---------------- 1 l

25 ml ---------------- x

x = (25 x 1) / 1000

x = 0.025 l

-Substitution

moles = 0.2 x 0.025

-Result

moles = 0.005

7 0

3 years ago

PLEASE HELP DUE IN 30 MINUTES NO LINKS PLEASE

hammer [34]

Answer:

B is the correct answer

Explanation:

If this answer is correct plzz mark me as brainliest plzzzz

7 0

3 years ago

What poisonous gas is found in the exhaust fumes of car engines?

Ugo [173]

The toxic gar expelled from the reaction between gasoline and oxygen in the vehicle's engine is both Carbon dioxide and monoxide

4 0

3 years ago

Read 2 more answers

A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr

sergey [27]

Answer:

184.62 ml

Explanation:

Let $p_1, v_1,$ and $T_1$ be the initial and $p_2, v_2,$ and $T_2$ be the final pressure, volume, and temperature of the gas respectively.

Given that the pressure remains constant, so

$p_1=p_2$ ...(i)

$v_1$ = 200 ml

$T_1= 26 ^{\circ}C = 273+26 =299$ K

$T_2= 3 ^{\circ}C = 273+3 =276$ K

From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

$p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)$

For the final condition,

$p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)$

Equating equation (i), and (ii)

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

$\frac{v_1}{T_1}=\frac{v_2}{T_2}$ [from equation (i)]

$v_2=\frac{T_2}{T_1} \times v_1$

Putting all the given values, we have

$v_2=\frac{276}{299} \times 200 = 184.62 \; ml$

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.

7 0

3 years ago

Should the line of best- fit travel through the origin of the graph ? Explain your reasoning

Finger [1]

<span>I would say only if one of your data points is the origin. But your experiment could have started with a non-zero velocity, for instance, which would rule out the origin as one of your data points. Even so, a "best fit" is not meant to be perfect, it is only meant to be the best that you can do with your particular data set.</span>

8 0

3 years ago

60\15A=help help help help help help help help help help​

60\15A=help help help help help help help help help help