Answer:
fingerprint!
Explanation:
sounds cooler, and it should have fewer people in the category, making a higher chance if placing if you do it.
Answer is: 0.5 dm³ to dissolve.
m(CuSO₄) = 11.2 g.
c(CuSO₄) = 0.140 mol/dm³,
V(CuSO₄) = ?
n(CuSO₄) = m(CuSO₄) ÷ M(CuSO₄).
n(CuSO₄) = 11.2 g ÷ 159.6 g/mol.
n(CuSO₄) = 0.07 mol.
V(CuSO₄) = n(CuSO₄) ÷ c(CuSO₄).
V(CuSO₄) = 0.07 mol ÷ 0.14 mol/dm³.
V(CuSO₄) = 0.5 dm³.
Answer:
No
Explanation:
The mass fraction is defined as:
where:
- wi: mass fraction of the substance i
- mi: mass of the substance i
- mt: total mass of the system
<u><em>The mass fraction of two substances (A and B), will be the same, ONLY if the mass of the substance A (mA) is the same as the mass of the substance B (mB).</em></u>
An equimolar mixutre of O2 and N2 has the same amount of moles of oxygen and nitrogen, just to give an example let's say that the system has 1 mole of O2 and 1 mole of N2. Then using the molecuar weigth of each of them we can calculate the mass:
mA= 1 mole of O2 * 16 g/1mol = 16 g
mB=1 mole of N2 *28 g/1mol=28 g
As mA≠mB then the mass fractions are not equal, so the answear is NO.
Answer:
The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.
Explanation:
The glycine is an amino acid with the following chemical formula:
NH₂CH₂COOH
The COOH functional group is what gives the acid properties in the molecule.
Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:
NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O
The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.
Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.
I hope it helps you!
