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scoray [572]
3 years ago
13

1,645.6 expressed in scientific notation equals?

Chemistry
2 answers:
12345 [234]3 years ago
8 0
1.6456 x 10^3 (ten to the third power)
gizmo_the_mogwai [7]3 years ago
6 0

Answer : The correct representation is, 1.6456\times 10^{3}

Explanation :

Scientific notation : It is defined as the method or a way or representation of expressing the given number which are too big or too small that is written in the decimal form. That means, it always written in the power of 10 form.

For example : 8000 is written as, 8\times 10^3

As we are given the digit which is, 1645.6

This number is written in scientific notation as :

1.6456\times 10^{3}

Therefore, the correct representation is, 1.6456\times 10^{3}

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Air containing 20.0 mol% water vapor at an initial pressure of 1 atm absolute is cooled in a 1- liter sealed vessel from 200°C t
chubhunter [2.5K]

Answer:

This solution is quite lengthy

Total system = nRT

n was solved to be 0.02575

nH20 = 0.2x0.02575

= 0.00515

Nair = 0.0206

PH20 = 0.19999

Pair = 1-0.19999

= 0.80001

At 15⁰c

Pair = 0.4786atm

I used antoine's equation to get pressure

The pressure = 0.50

2. Moles of water vapor = 0.0007084

Moles of condensed water = 0.0044416

Grams of condensed water = 0.07994

Please refer to attachment. All solution is in there.

6 0
3 years ago
What is the mole ratio of aluminum to chlorine in the compound aluminum
creativ13 [48]
1:3
The ratio of Al3+ ions to Cl− ions in the chemical formula is 1:3.
I’m sorry if this didn’t help I’m new to Brainly
6 0
3 years ago
Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ΔH° for the r
PolarNik [594]

Answer: -105 kJ

Explanation:-

The balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

The expression for enthalpy change is,

\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]

\Delta H=[(n_{N_2}\times B.E_{N_2})+(n_{H_2}\times B.E_{H_2}) ]-[(n_{NH_3}\times B.E_{NH_3})]

\Delta H=[(n_{N_2}\times B.E_{N\equiv N})+(n_{H_2}\times B.E_{H-H}) ]-[(n_{NH_3}\times 3\times B.E_{N-H})]

where,

n = number of moles

Now put all the given values in this expression, we get

\Delta H=[(1\times 945)+(3\times 432)]-[(2\times 3\times 391)]

Delta H=-105kJ

Therefore, the enthalpy change for this reaction is, -105 kJ

8 0
3 years ago
At room temperature (208C) and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
Ugo [173]

Total density of filled ball with nitrogen gas: \frac{0.12G+0.6524g}{0.560L} = 1.3792g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165g/L

Mass of the nitrogen gas : 1.165g/L \times 0.560L = 0.6524g

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4 0
2 years ago
Please help<br>What is the possible ions of vanadium?
svetlana [45]

V+5, V+4, V+3, and V+2

7 0
4 years ago
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